If 425 joules are absorbed from the higher temperature reservoir and 295 joules of that is passed on to the lower temperature reservoir, how much work has been done by the system?

Question

ericcrawford · Answer

anyone?

TheSmartOne · Answer

Uhh it's a quiet time right now so I'll give it a shot. Someone can correct me if I'm wrong

I feel like we need to be using the equation
$\Delta$U = Q - W

Where $\Delta$U is change in internal energy
Q is heat added to the system
W is work done by the system

Maybe I'm over thinking it
 Have you learned this formula yet?

TheSmartOne · Answer

Also, I'd like to welcome you to QuestionCove! Welcome aboard (:

ericcrawford · Answer

it sounds like I have there's just so many formulas, thank you!

TheSmartOne · Answer

Of course, it's not used offered. They teach it in the beginning and then they focus on other formulas like W=Fd

TheSmartOne · Answer

Often