Question

http://prntscr.com/nqy5xd

Answer 1

@Vocaloid

Answer 2

@Narad

Answer 3

Yes

Answer 4

http://prntscr.com/nqyb4n

Answer 5

yes

Answer 6

http://prntscr.com/nqybg0

Answer 7

Yes

Answer 8

http://prntscr.com/nqybvr

Answer 9

Yes

Answer 10

http://prntscr.com/nqyc7r

Answer 11

All ok

Answer 12

http://prntscr.com/nqycdf

Answer 13

All ok

Answer 14

http://prntscr.com/nqycu6

Answer 15

http://prntscr.com/nqydq2

Answer 16

http://prntscr.com/nqyf07

Answer 17

http://prntscr.com/nqyf8g

Answer 18

http://prntscr.com/nqyflv

Answer 19

http://prntscr.com/nqygip

Answer 20

http://prntscr.com/nqyhd0

Answer 21

http://prntscr.com/nqyhxn

Answer 22

http://prntscr.com/nqyijr

Answer 23

http://prntscr.com/nqyjb2

Answer 24

@Narad can you please tell me what those answers were for those questions please?^

Answer 25

because it isnt there anymore

Answer 26

Which one?

Answer 27

http://prntscr.com/nqycu6
http://prntscr.com/nqydq2
http://prntscr.com/nqyf07
http://prntscr.com/nqyf8g
http://prntscr.com/nqyflv
http://prntscr.com/nqygip
http://prntscr.com/nqyhd0
http://prntscr.com/nqyhxn
http://prntscr.com/nqyijr
http://prntscr.com/nqyjb2

Answer 28

you answered them before I just dont see the answers anymore

Answer 29

Thet have been removed

Answer 30

1st one
\[sinB= 0.88\]
The angle is
\ From my calculator, B=1.08

Answer 31

2nd question
\[tanB=0.34\]
Therefore, the angle is
\ From my calculator, B=0.33 rad

Answer 32

3rd question
\[cosA=0.23\]
So, the angle is
\[A=\cos ^{-1}(0.23)\]
From my calculator, the angle is
A=1.34 rads

Answer 33

4th question
sinB= 11/18
so, the angle is
\ From my calculator, the angle is B= 37.67º

Answer 34

5th question
From the drawing
\[sinA=2/4=1/2\]
Therefore,
the angle is
\[A= \sin ^{-1}(0.5)\]
From , the unit circle
A=30º

Answer 35

6th question
From the given triangle, by applying Pythagoras theorem
\[AB ^{2} = AC ^{2} +BC ^{2}\]
AC=5
BC=4
Therefore
\[AB ^{2}= 5^2+4^2 =25+16=41\]
so,
\[AB=\sqrt{41}=6.40\]

Answer 36

7th question
From the triangle XYZ,
\[\tan50º = YZ/XZ\]
but,
XZ= 6.1
therefore,
\[YZ=XZ*\tan50º\]
\[YZ=6.1*\tan50º = 7.27\]

Answer 37

8th question
In the triangle ABC, we have
\[tanA=BC/AC\]
BC= 4
AC= 5
Therefore,
\[tanA=4/5=0.8\]
And the angle is
\[A= \tan ^{-1}(0.8)= 38.66º\]

Answer 38

9th question
From the drawing
\[\tan50º=x/50\]
Therefore,
\[x=50*\tan50º= 59.59\]
The height of the building is
\[H= 5+x=59.59+5=64.59 ft\]

Answer 39

10th question
The ladder makes an angle of 45º and is 7 ft from the wall
Therefore, we have an isoceles triangle
By the Pythagoras theorem,
The length of the ladder is
\[l=\sqrt{7^2+7^2} = 9.90m\]
You can also use sin or cosine

Answer 40

http://prntscr.com/nr21ne

Answer 41

@Narad

Answer 42

The function to be graphed is

\[f(x)=\sin(x)-5\]
When x=0, \[f(0)=\sin(0)-5=-5\]
When \[x=\pi\], \[f(\pi)=\sin(\pi)-5=-5\]
When \[x=\pi/2\], \[f(\pi/2)=\sin(\pi/2)-5=1-5=-4\]
When \[x=-\pi/2\], \[f(-\pi/2)=\sin(-\pi/2)-5=-6\]
The domain is \[=\mathbb{R} \]
The range is\[y \in [-6,-4]\]

Answer 43

Okay but how would it look graphed?

Answer 44

Hmm I cant see it?

Answer 45

\[-1\le sinx \le 1\]
\[-1-5\le sinx-5\le1-5\]
\[-6\le f(x)\le-4\]
This is the range

Answer 46

no im just asking like it says we also have to graph it so can you show me how?

Answer 47

You calculate all the points by an incrementation of pi/2
x= -5pi, -4.5pi, -4.0pi, -3.5pi, -3.0pi, -2.5pi, -2.0pi, -1.5pi, -1.0pi,-0.5pi,0, 0.5pi, 1pi,1.5pi.2pi, 2.5pi. 3.0pi, 3.5pi,4.0pi, 4.5pi,5pi
you calculate all the point y= f(x)=sin(x)-5
And you plot the curve

Answer 48

but it says graph by radians?

Answer 49

@Narad ?

Answer 50

The maximum are at (-7pi/2,-3pi/2, pi/2, 9pi/2)

The minimum are at (-5pi/2, -pi/2,3pi/2,11pi/2)

Answer 51

okay but how can I graph it on this graph:

http://prntscr.com/nr3adh

Answer 52

@Vocaloid some input please

Answer 53

@Narad the next question is :http://prntscr.com/nr4ch4

Answer 54

domain and range? @Narad

Answer 55

The graph is as the attachement.
The domain is all real numbers
\[-1\le cosx \le1\]
\[-2\le 2cosx \le2\]
The range is\[ y \in [-2, 2]\]
The maxima are at (-4pi, -2pi, 0, 2pi, 4pi)
The minima are at (-3pi, -pi, pi, 3pi)

Answer 56

http://prntscr.com/nr4w2w

Answer 57

@Narad