Question

How many H atoms are present in a 5.79 ng sample of nitrobenzene, C6H5NO2?

Note: 1 ng is one nanogram.

Answer 1

@Vocaloid

Answer 2

So, I know how to solve a problem like this, but the nanogram is throwing me off

Answer 3

Can I just convert the nanogram to grams and solve this question normally?

Answer 4

yes

to go from ng to g you would just multiply by 10^(-9)

Answer 5

So,
5.79x10^-9 g C6H5NO2 x (1 mol / 123.06 g) = 4.705 x 10^-11 mol C6H5NO2
4.705 x 10^-11 mol C6H5NO2 x (5 mol H / 1 mol C6H5NO2) = 2.35x10^-10 mol H
2.35x10^-10 mol H x 6.022x10^23 atom /1 mol = 1.42 x10^14 atoms H

Is that correct?

Answer 6

You don't have to check if I did the math right, just the steps

Answer 7

yeah that's what i got too

Answer 8

Awesome, thank you so much!