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What mass of O is found in 61.7 g of Al2(SO4)3? Okay, so I did this, but for some reason I still got it wrong. :\
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@Vocaloid
61.7g to moles Al2(SO4)3, times the molar mass of oxygen, times 12?
61.7 g x 1 mol / 342.17 g = 0.18032 mol Al2(SO4)3 0.18032 mol Al2(SO4)3 x 16 g/1 mol = 2.88 g
why times 12?
1 mole of Al2(SO4)3 has 12 moles of oxygen atoms per the formula
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Ohhh, shoot I missed that. So 2.885 x 12 = 34.62 g
Thank you so much!
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