studydeep:
150.00 g of lead react with hydrochloric acid - write the balanced reaction this is what I came up with: Pb + 2 HCI → PbC12 + H2 What is the theoretical yield of lead (II) chloride in grams? using dimensional analysis
lowkey:
Yes, the reaction is balanced.
lowkey:
This problem is asking how much lead chloride would result in this reaction.
lowkey:
Do you know how to do dimensional analysis?
lowkey:
@studydeep
studydeep:
a little bit... its still confusing to me
lowkey:
Okay. BCA tables can help in these types of problems.
lowkey:
so first, we must convert the 150 grams into moles. Do you know how to do this?
studydeep:
no i don't
lowkey:
Alright, to convert grams to moles, you must divide the number of grams of the molar mass, which is the molar mass of the compound pb.
studydeep:
thats 207.2 right?
lowkey:
Yes! You are correct! the way to do dimentional analysis is this: 150.00g Pb x 1 mol Pb/207.2g Pb Do you understand that the numerator is the value you need, and that you need the number, unit, and thing for every dimentional analysis?
studydeep:
yes I understand that... and would i get 31080?
lowkey:
uhh nooo lol it's one over 207.2
lowkey:
it would be 0.72 moles of Pb
studydeep:
wait wait how? what
lowkey:
\[150.00~g~Pb \times \frac{ 1~mol~Pb }{ 207.2~g~Pb }\]
lowkey:
This form is called dimensional analysis.
studydeep:
oh I see now... my bad im stired so im not functioning right. I think I got this part of the dimensional analysis earlier today but I got stuck after this
lowkey:
I see. So now we need to create a BCA table. Do you know what those are?
studydeep:
no i dont think ive learned that
lowkey:
https://www.chemedx.org/sites/www.chemedx.org/files/powerpoint-stoichiometryrevisited-bcatables.pdf Can you read this real quick?
lowkey:
Tell me when you're done!
studydeep:
i don't think I can use that kind of table though bc ive never learned it.
lowkey:
Oh.
lowkey:
I guess we dont need it. Since the ratio of the Pb and PbCl2 is the same, we can assume that 0.72 moles of PbCl2 are produced.
studydeep:
I see... does the dimensional analysis continue at all?
lowkey:
Yes, it does. So then 0.72molPbCl2 times molar mass of PbCl2
studydeep:
its 289.1 g right?
lowkey:
yep! so multiply that number times 0.72
studydeep:
208.152?
lowkey:
yep!
studydeep:
would that be my final theoretical yield or is there more?
lowkey:
that is it
studydeep:
okay and would it go 0.72mol pB / 289.1 g for dimensional analysis or would it be the other way around?
lowkey:
it would be multiply
studydeep:
the multiply would go in the front?
lowkey:
where did you even get 'front'from
studydeep:
uhh by * 0.72mol pB / 289.1 g the / isn't to divide its for the dimensional analysis, right?
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