Explain set theory to me and the shading, please.
Shading, as in the venn diagrams?
yes
The primes confuse me and the complicated ones
@Shadow
The primes like \(X'\) means the elements that are not in set \(X\)
You have to work your way from the inside out. First find \(Z \cup X'\)
Better yet, here's what you do: First list the elements of \(Z\) then list the elements of \(X'\). The combination all the elements together with no repeats is \(Z \cup X'\)
@kaylak
okay so f,h,k,o,s,b,f,
now apply y
what does the extra prime mean?
I'll explain what it means.
Hang on for a minute.
But first, can you explain the set you just posted? What does it represent?
z and everything that is not in x
crap b h o is in x
f k s
Sorry let me correct an error I made earlier. I clearly confused you. This is the correct information. I typed too fast the first time. I suppose it would help to know that \(Z' = U - Z\) meaning the elements of the universal set minus the elements of \(Z\)
b u
Actually, that is correct but it is \(Z \cup X'\) is what we need to find. Maybe I didn't make a mistake afterall. we need the elements of Z plus the elements of the universal set that are not in \(X\)
f k s
Let me check that real quick
it disappeared
That was nothing
I don't get why its doing that. I not even posting that
Actually, I think you had it
One second.
\(\displaystyle \begin{array}{{>{\displaystyle}l}} ( Z\ \cup \ X') \ =\ \{f,\ k,\ o,\ s\} \ +\ \{b,\ f,\ h,\ k,\ o,\ s,\ u\} \ -\ \{b,\ h,\ o,\ u\}\\ =\{f,k,\ o,\ s\} \ +\ \{f,\ k,\ s\}\\ =\{f,k,o,\ s\}\\ \end{array}\)
That's what it is exactly
Now, the extra prime means the elements of the universal set that are not \(\{f,k,o,s\}\)
@kaylak are you still there?
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