Question

If 125 cal of heat is applied to a 60.0-g piece of copper at 21.0 ∘C , what will the final temperature be? The specific heat of copper is 0.0920 cal/(g⋅∘C) .

Answer 1

q = mc deltaT
you're given q (125 cals), m (60.0g), c (0.0920 cal/(g⋅∘C) and the initial temperature (21.0 deg. C)

so you can solve for delta T, then add that to the initial temperature to find the final temperature