Question

math help plzz

Answer 1

@Vocaloid

Answer 2

Do you know the graphical significance of \[f^{-1}(x)\]

It is the reflection of the original function over the line y=x. When you are just given points, with no easily detected function, you can't always use the algebraic method.

Instead convert them to (-y,-x) from the given (x,y)


Then, do you know what is a one-to-one function? A one-to-one function is where every exact element in the range of the function corresponds to only ONE input in the domain.
A quadratic function is never one-to-one because a certain element in the range has 2 inputs, while a cubic would be. Graphically you would use the horizontal line test, but given points you just check to make sure every output corresponds to a unique input.

For the last part, recall that the inverse of a function is not always a function.

Answer 3

A good way to make sure is if the graph of the original function doesn't pass the horizontal line test, then the inverse isn't a funciton

Answer 4

function*

Answer 5

Check the table for \[f^{-1}(1)\] again.

Answer 6

Yeah, there is an error on the 3rd, 4rth, and 5th row

Answer 7

Nah I think the rest of his rows are correct.

Answer 8

ah yeah I myself didn't check it properly.