Question

i need someone to correct a minor mistake in my solution please :)

Answer 1

i wanna ask how did they make the -2e^2y to the denominator...with sign changed??

Answer 2

tthinking

Answer 3

@Hero

Answer 4

Tomorrow. I need to sleep someone else can help, but you should review implicit differentiation. It seems you are being to casual rather than careful with the rules and your steps.

Answer 5

there’s only 4 implicit diff questions in the textbook and one on the test but i’m studying it in the book u gave me. it’s not that bad tbh. i think i can do it... thanks master!!

Answer 6

The derivative of \[e ^{2y}\] is an implicit derivation

Answer 7

also i can’t find the 3rd derivative of this question...

Answer 8

@Hero

Answer 9

In the second line of calculation of
\[f''(x)\]
simplify from numerator and denominator
\[x^2+1\]

Answer 10

I did take \[X^2+1\] common out at the very last step of 2nd derivative but it messes up the answer of 3rd derivative. I had to rewrite all over again because of that mistake.

Answer 11

Everything is quite alright up to the calculation of \(f''(x)\). However, when computing \(f'''(x)\), you defined \(g(x) = -2x^2+2\), so \(g'(x) = -4x\) instead of \(-4x^2\).

Also, the denominator can be simplified, since \([(x^2+1)^2]^2= (x^2+1)^4\). This allows you to cancel some of the terms in the numerator instead of having to expand everything out.

Answer 12

Omg...thanks for catching that mistake... now i can do this question. Thanks bro..ily :)