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Mathematics 15 Online
Ballery1:

Math question.

Ballery1:

For the applications of derivatives... I want to know ...how do I figure out that tipping point in any curve of the graph where the curve shifts from either positive to negative or negative to positive. I guess you can call it the point of vertex...but not every function will face the symmetry to the origin. (0,0)

Ballery1:

*but not every function will have symmetry to the origin (0,0)* correction. :)

Ballery1:

|dw:1569455717214:dw|

Ballery1:

I’m looking for a method to find the shifting point of polynomial functions with multiple shifting points... such as this.... |dw:1569455857537:dw|

mhchen:

So the first derivative tells you the slope. When at some point the slope changes from positive to negative or negative to positive, there's your shifting point

mhchen:

https://www.desmos.com/calculator/vbicctilyf here's an example

mhchen:

yeah you're right, when the derivative is 0, there's your shifting point

Ballery1:

Here’s what I did... and it gave me all the shifting points

Ballery1:

I have a question... so for a simple function such as \[F(x) = 5-2x\] |dw:1569459404173:dw|

Ballery1:

since a function like that doen’t Have any bounds or limits... it only has a decreasing interval...so how do i state it’s interval again?

mhchen:

\[(-\infty , \infty)\]

Ballery1:

I see now... thanks mate :)

Ballery1:

A very quick question... about the interval (-infinite, +infinite). Why’s there a positive infinite in the interval ?? So as x approaches +infinite...that’s going from LHS to RHS, the graph seems to decrease...

mhchen:

That's the domain. The range goes to negative infinity though

Ballery1:

I think i got it. Thanks bro :)

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