Question

Hero I have a question

Answer 1

f(x)=2x^4+29x^3+72x^2+5x-12; -3
How would I find all the zeros using the given zero? I don't remember this

Answer 2

Also sorry I do not know how to make the to the power symbol so it doesn't look messy

Answer 3

\(\bf{f(x)=2x^4+29x^3+72x^2+5x-12; -3}\)

Answer 4

Thank you c:

Answer 5

Since you already have a given zero. Use synthetic division to factor \((x + 3)\) out from the expression of \(f(x)\)

Answer 6

thats it?

Answer 7

I thought that's what you're currently studying.

Answer 8

If you don't know it then you'll just have to use regular long division

Answer 9

No I know how to divide that way, I just didn't know if that is all I had to do. I was overthinking it ig

Answer 10

You're welcome

Answer 11

Thank you c:

Answer 12

Wait, doesn't that just use the given zero and not help me find the others? o.O

Answer 13

I already explained to you what to do. Synthetic division is the quickest way to solve this. The zero only gives you one of the factors of \(f(x)\). You have to use long division or synthetic division to find the rest.

Answer 14

uh

Answer 15

(x+3)(2x^3+23x^2+3x-4) ?

Answer 16

You need to factor out the \(x\) from the expression for \(f(x)\) before performing the synthetic division.

Answer 17

What
doesnt that just become zero

Answer 18

Any way you could please do the equation step by step with me? e.e

Answer 19

Ah I overlooked the -12 so \(x\) is not a factor

Answer 20

I have no clue anymore

Answer 21

Just do the division of \(f(x)\) over \((x + 3)\)

Answer 22

You have to factor the expression afterwards to find the remaining factors of \(f(x)\)

Answer 23

If you're stuck, show where you are stuck. Post your division attempt.

Answer 24

Ima just like, not do this e.e

Answer 25

BUT THANK YOU
Sorry my brain can't process what you say

Answer 26

Perform this operation:
\(\dfrac{2x^4+29x^3+72x^2+5x-12}{x+3}\)

Answer 27

Using the long division format

Answer 28

nO
But thank you