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zarasht:
Determine the number of moles in 4.21 x 10^23 molecules of CaCI2?????
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justjm:
Use dimensional analysis again \( 4.02\ molecules\ CaCl_{2}\ \cdot\ \frac{1\ mol\ CaCl_{2}}{6.23\ \cdot10^{23}\ molecules} \)
justjm:
Oops BTW I meant 4.21 x 10^23, my eyes completely misread that
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