Question

The domain for f(x) and g(x) is all real numbers. Let f(x) = 3x^2 + x-7 and g(x) = x^2 + 4x-5
Find (f-g)(x).

Answer 1

@dude

Answer 2

\[\rm (f-g)(x)=f(x)-g(x)\]

Answer 3

\[\rm \color{Red}{f(x) = 3x^2 + x-7}, ~~~\color{blue}{g(x) = x^2 + 4x-5}\] \[\rm (f-g)(x)=\color{Red}{f(x)}-\color{blue}{g(x)}\] \[\rm (f-g)(x)=(\color{Red}{3x^2 + x-7})-(\color{blue}{ x^2 + 4x-5})\]
1) distribute the negative sign
2) combine like terms

Answer 4

\[\rm (f-g)(x)=(\color{Red}{3x^2 + x-7})-(\color{blue}{ x^2 + 4x-5})\] is same as
\[\rm (f-g)(x)=(\color{Red}{3x^2 + x-7})-\color{orange}{1}(\color{blue}{ x^2 + 4x-5})\]

Answer 5

@Nnesha, thanks I got it, I think

Answer 6

I got 3x^2-3x-2

Answer 7

how?

Answer 8

I subtracted 3x^2-x^2, which game 2x^2

Answer 9

then, I subtracted x-4x which equals -3x

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @eviant
I subtracted 3x^2-x^2, which game 2x^2
\(\color{#0cbb34}{\text{End of Quote}}\)
yes correct so it should be 2x^2

Answer 11

finally, I did -7+5, which gave me -2

Answer 12

good job!

Answer 13

@Nnesha is it okay to add the last part?

Answer 14

the -7+5 part?

Answer 15

@dude @AngeI

Answer 16

it will NOT be okay if you don't add.

Answer 17

that's part of the answer "the constant" term

Answer 18

(f-g)(x)= `2x^2-3x-2`

Answer 19

@Nnesha so its correct, right?

Answer 20

yes