Question

Roots of y=(x-2)^2

Answer 1

Same procedure. To find the roots of the function, set y to 0, then solve for \(x\)

Answer 2

Lemme put it in the calculator first

Answer 3

No, you don't need any calculator for this.

Answer 4

Really

Answer 5

All you need to do is follow the procedure. You need more pencil and paper than calculator for this.

Answer 6

(0,2)(2,0)?

Answer 7

It seems you don't even know when to use pencil/paper and when not. Not every problem requires immediate calculator retrieval.

Answer 8

Shhh go easy on me

Answer 9

Thing is, you can post an answer but you still have to show the work you did to arrive at your result.
If you're unable to do that, it means you have not understood how to solve the problem.

Answer 10

NOPE I don't have to show work because it's in the calculator, so I'm not required to

Answer 11

If that's true that you have the calculator and don't need to show your work, then what do you need me for? The calculator is giving you the answers.

Answer 12

But what you posted above does not appear to be correct as written.

Answer 13

But..it's not because I still don't know it or how to find it..heh

Answer 14

In order to find it, you have to use pencil and paper but you just said you're not required to use it.

Answer 15

Not if I use the calculator, which I'm not right now, so help me please and thank you
:)

Answer 16

Let's do another example

Answer 17

Suppose \(y = (x - a)^2\) Find the roots:

To find the roots, set \(y = 0\), then solve for \(x\) as follows:

\(0 = (x - a)^2\)

Apply the root to both sides:
\(\sqrt{0} = \sqrt{(x - a)^2}\)

Simplify
\(0 = x - a\)

Add \(a\) to both sides:
\( \pm a = x\)

The roots of the function are \((-a,0)\) and \((a,0)\)

Answer 18

For some reason @allison doesn't consider this help or doesn't understand this.

Answer 19

I just shewed you the whole shebang.

Answer 20

That's how to find the roots verbatim and if you don't understand that. It's basic algebra. Without understanding that, good luck with higher levels.

Answer 21

My brain cannot process this, I don’t understand it

Answer 22

I’m in intergrated 2

Answer 23

Then I'm afraid you'll have to drop out and go back to pre-algebra. Even the students who struggle with algebra are able to recognize and understand "set variable y equal to zero then solve for x" procedures.

Answer 24

I guess it’s harder to understand through text

Answer 25

It's just a communication issue. When you post questions, smart students know to also post the instructions given along with the question.

Answer 26

I’m a visual learner, like I need to watch you physically do it and then I can copy the same steps in a different equation or problem

Answer 27

Wait I will show you the sheet

Answer 28

From what you posted in the message, it seems you're only required to use a graph to find all these elements you're required to find. It seems you don't have to do the algebra but now you need to learn how to graph the function using a graphing calculator and how to recognize elements such as "vertex", "roots", "intercepts"

Answer 29

I see but now that you have posted your document it does not say which procedure to use to find all those things. I assume a combination of both. However, the default procedure is algebra for most those elements.

Answer 30

I can recognize the vertex, axis of symmetry, direction of opening, minimum or maximum, and interval increase and decrease. The roots is the part that I don’t know, and I’m confused about.


Do you look at where the vertex touches the axis’? And identify the points?

Answer 31

Any points of a function that touches the x-axis is a root.

Answer 32

What about the y axis? It’s an automatic 0?

Answer 33

You don't worry about the y-axis when it comes to finding roots. The only exception is if the point touches both the x and y axis at the same time. The only point that does that is (0,0)

Answer 34

Okay

Answer 35

It’s touching the y and x axis in this graph

Answer 36

It looks like (2,0)

Answer 37

And the other one is (2,0)

Answer 38

(0,2) **

Answer 39

Suppose \(y = (x - a)^2\) and you're tasked with identifying the roots:


The roots of the function are \((-a,0)\) and \((a,0)\)

Answer 40

Pay close attention to the points and the \(a\) values

Answer 41

OH

Answer 42

-2

Answer 43

So (-2,0) (2,0)

Answer 44

Correct finally.

Answer 45

WHOOP

Answer 46

Okay y=-(x-5)^2

Answer 47

Vertex is (5,0)

Answer 48

I think this is a bad time for me. I thought maybe you just had one question. You have an entire battery of questions and I am unable to help with them all at this time. Sorry

Answer 49

I have my own work I need to finish unfortunately.

Answer 50

Okay. I’ll solve them myself and maybe check them with a robot math teacher