Question

What coefficient would go in front of HNCO to balance this equation? the pic is in the comments

Answer 1

\[\rm Left ~side: \]\[\rm H: 1\]\[\rm N: 1\]\[\rm C: 1\]\[\rm O: 1\]
\[\rm Right ~side: \]\[\rm H: 6\]\[\rm N: 6\]\[\rm C:4\]\[\rm O: 2\]
The number of element on reactant side should be equal to number of element on product side.

Answer 2

btw
we multiply each element inside the parenthesis by 3

Answer 3

So my answer choices are 3,4,5,6 and thank you for the help! But what I dont get is that I can only put on the left side one number to balance it, is that even possible?

Answer 4

a coefficient and plus in order to balance it out you can put a subscript

Answer 5

I know its not 6 because my friend had this before and she got 6 wrong so the answer can be either 3,4,5, or none of the above and its multiple choice so I cant add anything

Answer 6

for this type of questions you have to go back & forth to make sure all the elements satisfied with that one coefficient

Answer 7

lets find out why it is not 6.

Answer 8

In order for it be a 6,I think there has to be a 3 in front of CO2

Answer 9

And I cant do that

Answer 10

if you put 6 as a coefficient that means all the other elements are also 6
H:6
N:6
C:6
O:6

Answer 11

Yes

Answer 12

Since the question is asking for coefficient for left side that means you can't make a change on the right side.

Answer 13

yeah i cant

Answer 14

so how would you get 2 O on the left side?

Answer 15

I cant the choices dont give me an option, I am wondering now if its a mistake the teacher did.

Answer 16

lets forget about the answer choices for a second. I am trying to help you understand the method so you can do the rest of the questions on your own.

Answer 17

Oh okay well if I were to put a 6 on the left side in order to balance it out I would have to add a 3 in front of CO2

Answer 18

that's correct. But for this question, we can't change anything on the right side. we need to make all the elements on the left side equal to the number of the elements on the right side. So how would you get
H: 6
N: 6
C: 4
O: 2

Answer 19

one more hint: since all the elements are not equal to 6, we need to put some subscript.

Answer 20

Okay so if we did with subscripts wouldnt it be

Answer 21

that's correct!

Answer 22

Thank you for the help! Now I need to talk to my teacher why its like that

Answer 23

like what ?

Answer 24

why the answer choices dont match up

Answer 25

what do you have for the answer choices ?

Answer 26

3,4,5,6 and no coefficient needed

Answer 27

oh okay one second.

Answer 28

okay

Answer 29

yeah confirm with the teacher to make sure there is no typo
The wording of the questions is like they are just asking to find a number that will balance the equation without even messing up with the right side. But lets say if we put 3 in front of Co2 and 3 in front of HNCO and then put a subscript of 2 for all the elements \[\rm 3 H_2N_2HC_2O_2\] but doesn't seems right to me

Answer 30

Yeah because it wouldnt work for Oxygen, but thank you for helping me understand this! Much appreciated:)

Answer 31

it will work for oxygen.
O will be 6 on both sides.\[\rm 3H_2N_2C_2O_2 \rightarrow C_3N_3(NH_2)_3 +3CO_2\]

Answer 32

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mimih
Yeah because it wouldnt work for Oxygen, but thank you for helping me understand this! Much appreciated:)
\(\color{#0cbb34}{\text{End of Quote}}\)
my pleasure!

Answer 33

Oh okay thanks anyways!

Answer 34

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mimih
Oh okay thanks anyways!
\(\color{#0cbb34}{\text{End of Quote}}\)