Question

i have a question.

Answer 1

also, can someone tell me what have i done wrong on line 2???

Answer 2

@imqwerty

Answer 3

why's there an error on line number 9??

Answer 4

```
//
// Conversion - Program to convert temperature from Celcius degrees into Fahrenheit:
// Fahrenheit = Celsius * (212 - 32)/100 + 32)

#include <cstdio>
#include <cstdlib>
#include <iostream>

int main(int nNumberofArgs, chars * pszArgs[])
{
//enter the temperature in Celsius
int celsius;
cout << "Enter the temperature in Celcius:";
cin >> celsius;

//calculate conversion factor for Celsius
//to Fahrenheit
int factor;
factor = 212 - 32;

//use conversion factor to convert Celsius
//into Fahrenheit values
int fahrenheit;
fahrenheit = factor * celsius/100 +32;

//output the results (followed by a Newline)
cout << "Fahrenheit value is:" ;
cout << fahrenheit << endl;

//wait until user is ready before terminating program
//to allow the user to see the program results
cout << "Press Enter to continue..." <<emdl;
cin.ignore(10, '\n');
cin.get();
return 0;
}

```

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1

\(\color{#0cbb34}{\text{End of Quote}}\)
you use \(\color{blue}{endl}\) whenever you want to start writing from a new line
endl is similar to the new line character \(\color{green}{\backslash n}\) which can be used instead of endl to denote a new line
it's not at all necessary to use endl, you just use it whenever you want to start from a new line.

Answer 6

i see. i have few more questions :)

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1
also, can someone tell me what have i done wrong on line 2???
\(\color{#0cbb34}{\text{End of Quote}}\)
i think stdafx.h is only limited to VS Code? you might have to copy the stdafx file into your project folder from VS Code to make it run

just comment out the second line, you don't need it anyways bcz you're just using cout

Answer 8

instead of that *stdafx.h* i inserted stacked and the code worked. idk why ? lol

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1
instead of that *stdafx.h* i inserted stacked and the code worked. idk why ? lol
\(\color{#0cbb34}{\text{End of Quote}}\)
what's stacked? lol

Answer 10

what does that mean? i'm scared *~*
int ain (int nNumberofArgs, chars * pszArgs) what does the stuff in the brackets represents?

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1
what does that mean? i'm scared *~*
int ain (int nNumberofArgs, chars * pszArgs) what does the stuff in the brackets represents?
\(\color{#0cbb34}{\text{End of Quote}}\)
nvm,
it's \(\large\color{green}{{char}}\) and not \(\large\color{red}{chars}\)

Answer 12

no but i need to know what's *nNumberofArgs* and *pszArgs* mean?

Answer 13

add this as well: using namespace std;

Answer 14

what's Args? and pszArgs?

Answer 15

the main function is the first function that executes so if you wanted to parse some arguments into the main function you'd do you right when you invoke your program from the command line


int main(int nNumberofArgs, char * pszArgs[])

those arguments refer to the command line arguments,

so if you do g++ fileName.cpp x y z a b c
then the value of nNumberofArgs will be 6 and you pszArgs will be an array having elements as {'x', 'y', 'z', 'a', 'b', 'c'}

Answer 16

what do you mean by "Parse some arguments into the main function"? i'm sorry, idk these technical words.

Answer 17

Also
```
// This program calculates the user's pay.
#include <iostream>
using namespace std;

int main()

{
double hours, rate, pay;

// Get the number of hours worked.
cout <<"How many hours did you work?" ;
cin >> hours;

// Get the hourly pay rate.
cout <<"How much do yo uget paid per hour?" ;
cin >> rate;

// Calcualte the pay.
pay = hours * rate;

//Display the pay.
cout << "You have earned $ " << pay << endl;
return 0;

}

``` on line 8, why's there a "double" beside hours, rate, pay?? what does it mean ?

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty
the main function is the first function that executes so if you wanted to parse some arguments into the main function you'd do you right when you invoke your program from the command line


int main(int nNumberofArgs, char * pszArgs[])

those arguments refer to the command line arguments,

so if you do g++ fileName.cpp x y z a b c
then the value of nNumberofArgs will be 6 and you pszArgs will be an array having elements as {'x', 'y', 'z', 'a', 'b', 'c'}
\(\color{#0cbb34}{\text{End of Quote}}\)
correction-
it should be-
$ g++ filename.cpp -o main
$ ./main x y z a b c
instead of $ g++ filename.cpp x y z a b c

Answer 19

double is a datatype, just like int and char
use it whenever you're dealing with decimal values

Answer 20

does it help calculate decimal values or what ?

Answer 21

yeah, you can't work with decimal values if your variables are int, you need to have a double or float

Answer 22

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1
what do you mean by "Parse some arguments into the main function"? i'm sorry, idk these technical words.
\(\color{#0cbb34}{\text{End of Quote}}\)
are you familiar with functions?

Answer 23

i'm only familiar with like four functions and even they're sucking the soul out of my life rn. int, bool, void and char

Answer 24

those are not functions

Answer 25

oof RIP

Answer 26

are they called variables ?

Answer 27

int, bool and char are primitive data types and void is a return type

Answer 28

i was literally gonna ask you about this list of things i have saved as a picture. i was gonna ask you, do i need to remember all of them and their applications???

Answer 29

you don't have to memorize that

Answer 30

even for the exams and test ?

Answer 31

it's like how you meet people, you don't have to memorize their names, and faces you just get familiar with them over time? lol

Answer 32

i see... so what were you talking about functions??

Answer 33

doesn't the function starts from int main() ? so like everything inside the curly brackets is the function ???

Answer 34

main() is a function, but you can have more functions

Answer 35

before starting functions you should atleast know what a return type is and the concept of datatypes

Answer 36

listening* :) <3

Answer 37

```
#include<iostream>
using namespace std;

void function1(){
cout<<"I'm Speaking from function1";
}

int function2(){
return 2;
}

int function3(int a, int b){
reuturn a+b;
}

int main(){
cout<<"Hello World";

function1();

int x = function2();

int z = function3(1,6);

return 0;
}
```

Answer 38

i've made 4 functions in this example

Answer 39

what if i run them??? what will i get?

Answer 40

i guess you didn't make every function a returning function correct?

Answer 41

yep function1 is void

Answer 42

void functions don't have to return anything

Answer 43

why does it look so intimidating ?

Answer 44

i'll explain it, it's rlly not that complicated

Answer 45

so there are four functions
their names: main, function1, function2, function3

Answer 46

i'll start by explain what each function does and then we'll see how to program runs

Answer 47

listening* :)))))))))))))

Answer 48

function1

the return type of function1 is \(void\)
so it doesn't have to return anything

whenever the function1 is called it just does what it's supposed to do and ends without returning anything

in this case, the function1 outputs this string: I'm Speaking from function1

Answer 49

how to know the reuturn type of a function?
it's specified before the name of the function

\(\color{green}{void~}{~function1(){ ... }}\)

Answer 50

i see, i have a quick question here master. :)))))))))
so if you're running 4 different functions and 3 of them are return functions. how will it show on the cmd?? like do you have to draw long horizontal lines between each function to distinguish each one??? if not...can you still do it?

Answer 51

master, did you mean "return" or "reuturn"? please clarify that :)))))

Answer 52

nope you don't have to draw any lines lol, we'll come to that later
and yes *return

Answer 53

icy now

Answer 54

for now, just know what each function is supposed to do, after that we'd see how all the functions get executed

Answer 55

okie dokie :))))))))

Answer 56

btw i can't run your code on my silly code block *~*

Answer 57

is it clear what function1 is supposed to do when it gets called?

Answer 58

because i have like 3 different projects opened already :/

Answer 59

i'm trying to absorb this. please give me few minutes to make sense of all this :)))))

Answer 60

you can run it on any online IDE

i made some fixes in the code-
https://ide.geeksforgeeks.org/zafi4XrTNt

Answer 61

oh yes i see now.... so what you want to do with a function is define by the name of the function in the very beginning... if you want to calculate integers... you put int, if you want no return.. you put void, if you are working with characters, you put chars etc

Answer 62

wdym by define the name of the function at the very beginning?

Answer 63

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1
oh yes i see now.... so what you want to do with a function is define by the name of the function in the very beginning... if you want to calculate integers... you put int, if you want no return.. you put void, if you are working with characters, you put chars etc
\(\color{#0cbb34}{\text{End of Quote}}\)
you can stick to this definition for now, but it's not exactly perfect

Answer 64

one second plz. i'm trying to find an example...

Answer 65

aight

Answer 66

that's what i mean... like you wrote 4 different types of functions... each one has its own function and its own purpose.

Answer 67

o so i have a question... so know when you put cout and cin.....is it true that when you tpe cout the arrows are always pointing to the left like this << and when you type cin, the arrows are pointing to the right like this >>??please clarify that :))

Answer 68

yep, it has to be like cout << and cin >>

Answer 69

ok thanks ... i'm teaching myself how to print anything and i tried stuff in the list form and they're not showing up for some reason... one sec let me post.

Answer 70

```
#include <<iostream>>

using namespace std;

int main;
{

cout << "Need For Speed Carbon!" << endl;
cout << "King of fighters" << endl;
cout << "Density" << endl;

return 0;
}

```

Answer 71

what am i doing wrong here master? :)))))))

Answer 72

the first line, it should be #include<iostream>

Answer 73

do i not.....nvm o///o

Answer 74

```
#include <iostream>

using namespace std;

int main()
{

cout << "Need For Speed Carbon!" << endl;
cout << "King of fighters" << endl;
cout << "Density" << endl;

return 0;
}
```

Answer 75

why is this still not printing??? *~*

Answer 76

i've corrected everything :/

Answer 77

what error does it throw?
did you save it / compiled before running?

Answer 78

it's working fine on the online IDE https://ide.geeksforgeeks.org/qhapN0yDuc

Answer 79

it says return wasn't declared i nthe scope

Answer 80

this is what i'm getting

Answer 81

it could be because return 0; isn't aligned properly

Answer 82

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1
this is what i'm getting
\(\color{#0cbb34}{\text{End of Quote}}\)
that should be *return

Answer 83

run this instead-
i fixed some bugs
```
#include<iostream>
using namespace std;

void function1(){
cout<<"I'm Speaking from function1"<<endl;
}

int function2(){
return 2;
}

int function3(int a, int b){
return a+b;
}

int main(){
cout<<"Hello World, I'm speaking from the main function"<<endl;

function1();

int x = function2();

int z = function3(1,6);

cout << "x is: " << x << endl << "z is: " << z << endl;
return 0;
}

Answer 84

i think the reason it isn't working because i have multiple projects opened...

Answer 85

let me close them and run em one by one.

Answer 86

yup, your code worked just fine. let me test each of them one by one.

Answer 87

```
//
// Conversion - Program to convert temperature from Celcius degrees into Fahrenheit:
// Fahrenheit = Celsius * (212 - 32)/100 + 32)

#include <cstdio>
#include <cstdlib>
#include <iostream>

int main(int nNumberofArgs, char * pszArgs[])
{
//enter the temperature in Celsius
int celsius;
cout << "Enter the temperature in Celcius:";
cin >> celsius;

//calculate conversion factor for Celsius
//to Fahrenheit
int factor;
factor = 212 - 32;

//use conversion factor to convert Celsius
//into Fahrenheit values
int fahrenheit;
fahrenheit = factor * celsius/100 +32;

//output the results (followed by a Newline)
cout << "Fahrenheit value is:" ;
cout << fahrenheit << endl;

//wait until user is ready before terminating program
//to allow the user to see the program results
cout << "Press Enter to continue..." <<emdl;
cin.ignore(10, '\n');
cin.get();
return 0;
}
``` i'm getting error on line 14, 28, and 32

Answer 88

i'm getting errors on line 14, 28, and 32. what am i doing wrong master? :))))))

Answer 89

you forgot using namespace std;

Answer 90

oof... can u tell which line???

Answer 91

#include <cstdio>
#include <cstdlib>
#include <iostream>
\(\large\color{blue}{using~namespace~std}\)

Answer 92

yay!! it worked!! WOOOOOOOOOOOOOOW! XD

Answer 93

yeah XD

Answer 94

lmao you should be debugging it yourself

Answer 95

i literally just started programming like less than 2 days ago... XD gimme some time master

Answer 96

also, can you please tell me if i need to write all those three preprocessors at the top???

Answer 97

wouldn't just iostream do the trick ?

Answer 98

yep, you just need iostream

Answer 99

okie dokie :)))

Answer 100

btw what is the first two preprocessors are used for?

Answer 101

let's see if my code knows that at -45 F the celsius is also -45 khekhekhekhe

Answer 102

i don't exactly know but ig cstdlib have functions which can be used to allocate memory from the heap and cstdio probaby has some input output functions

Answer 103

ok thanks :))))))

Answer 104

np