dddarryl:
calculate the grams of CO needed to react with the excess of Fe2O3 tp produce 104.9 grams of Fe. Fe= 55.85g; C= 12.01 g;O=15.99
DuarteME:
First, you should write the equation describing the reaction. Since \(\textrm{CO}\) is reacting with \(\textrm{Fe}_2\textrm{O}_3\) to produce \(\textrm{Fe}\), we see that the other reaction product must be \(\textrm{CO}_2\). Therefore, the equation must be: \(\square \textrm{ CO (g)} + \square \textrm{ Fe}_2\textrm{O}_3\textrm{ (s)} \to \square \textrm{ Fe (s)} +\square \textrm{ CO}_2\textrm{ (g)}.\) We can now see that the equation is not yet balanced: we still need to fill in the \(\square\)'s with coefficients in order to ensure that the number of atoms of each species is the same both on the reactants and on the products. Can you see how we can achieve that?
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