Which statement best demonstrates why the following is a non-example of a polynomial? The expression has a variable raised to a negative exponent. The expression has a variable in the denominator of a fraction. The expression has a negative coefficient. The expression has a variable raised to a fraction.
This question again.... @justus
Alright so right off the bat A is eliminated
Ya
Hmm
Can we come back to this question later
Ya.
Organize the following expressions from greatest to least by number of terms: I.x + 2xyz II. 9x2yz III.18x2 + 5ab − 6y IV. 4x3 + 3x2 − x − 4 III, IV, I, II IV, I, II, III IV, III, I, II III, II, IV, I
Expression I x+2xyz is 2 terms Expression II 9x^{2} yz is 1 term Expression III 18x^{2}+5ab-6y is 3 terms Expression IV 4x^{3}+3x^{2}-x-4 is 4 terms
IV, III,I,II
is this right?? Organize the following polynomial expressions from least to greatest based on their degree: I. x + 2xyz II. 9x3y2 III. 18x2 + 5ab − 6y IV. 4x4 + 3x2 − x − 4 III, I, IV, II <--- This one! IV, I, II, III III, II, IV, I IV, III, I, II
Yes
YESSSSSSSSS okey. Um..okey 1 min
Alright
wait for the last one that u did....i dont get it...howw....how is that the answer??
Its about the degrees right???
No its about the terms
You count how many terms there are in each expression
And then put it from greatest to least
Oh....so I have been doing it wrong for a while :(
That might explain my C
Oh its okay now you know
No.. everyone makes mistakes its okay
And math is pretty tricky it takes practices and there's a ton of rules
Organize the following polynomial expressions from least to greatest based on their degree: I. x + 2xyz II. 9x3y2 III. 18x2 + 5ab − 6y IV. 4x4 + 3x2 − x − 4 III, I, IV, II IV, I, II, III III, II, IV, I IV, III, I, II So is the first option correct?? :\ or no?
wait ya this one says based on "degree"!!
Yes I believe so
:O OOOOOOOOOOHHHHHHHH
Yes
back to the super confusin one now D:
Oh yes
I think it is B...the second option
You are correct!
Actually wait let me see
Yes lets put B and hope its right
Might be D
Ughhhh I hate the suspenceee. I feel like imma faillll
Oof. No you won't
90!!!!!!!!!
Thank you!!
Woohoo!!!!!!!!!
You did your best. I was wishing you a 100%!
c
You're welcome
It's okay. :)
The confusing one is the one we got wrong
Damn it XD
Im sorry for it being wrong
Eh it's fine. THANK YOU.
Good luck on this class! ✨
And always remember use ALL your attempts
Thanksss...im failinnggg
I have a C..........................
No don't reinforce it
Its okay you can do it!
okey Thanks!
its c
Tip #1 Use all you attempt Tip #2 Take your time Tip #3 Get help if your really stuck Tip #4 Don't give up
Tip #5 practice and practice
I GIVE UP ALL THE TIME MATH IS HARD we should only have to add number sub number and multilpy number not NO X<Y<Z
wht we finna use xyz for when we in the real world
lol
I am going to have a help session with the teacher on the 7th...
IKR!! When r we EVER gonna us this
use*
i feel ya
like to b a drug dealer all u needa do is no how to use a scale n for a cashier or plumber or any other job u not using xyz lol
lol oofff
:| o..............k.................................
We won't use it in real life but that's just how school works they like to put students under pressure 😐
D: I is under ultimate pressure
I understand
dat true
im under pressure evryday bc im homeschooled
My mom.......she wants the very best for me...so i need to get the very best grades...im in FLVS/LVIP
Hopefully you get the best grades
im failing in biology
For the confusing one, \(\color{#0cbb34}{\text{Originally Posted by}}\) @justus Might be D \(\color{#0cbb34}{\text{End of Quote}}\) Perfect job @justus, it's D. Fractional powers cannot be considered as polynomials because it adds a restriction to the domain. A and B are the same thing. A variable raised to the negative power is the same as a variable in the denominator. \(x^{-n}=\frac{1}{x^n}\) And in the problem, there was no variable in the denominator.
General hierarchy of relations: -To be a relation, you just need any set of values of x corresponding to y, or vica versa. -To be a function, you must fulfill the requirements of a relation + have a dedicated x value for any y value. X values cannot repeat -To be a polynomial, you must fullfill the requirements of a function + have no domain restrictions (no variables in denominator, no fractional degrees) -To be an injection, you must fullfill the requirements of a function + have the inverse of the relation be a function. polynomials and injections are independent.
Thank you justjm.
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