Question

Look at the figure below:

An image of a right triangle is shown with an angle labeled y.

If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°? (6 points)

Group of answer choices

cos y° = b divided by 6

cos y° = 6b

cos y° = 6a

cos y° = 6 divided by b

Answer 1

https://cdn.flvsgl.com/assessment_images/geometry_v16_gs-xml/94744_55a911e2/image0014e2d9887a.gif

Answer 2

@dancingdancer you can put an @ symbol before any user name to tag them to your question if you need help.

Answer 3

@Hero or @darkknight pls help!!

Answer 4

So \(\sin y^{\circ} = \dfrac{a}{6}\) and \(\tan y^{\circ} = \dfrac{a}{b}\). @dancingdancer how do we represent this on the rignt triangle?

Answer 5

sorry, I was afk, @Hero help him/her

Answer 6

@dancingdancer do you want help with setting it up?

Answer 7

Yes, can you please help me set it up. These types of questions are very confusing for me to understand.

Answer 8

Okay so basically the definitions of sine and tangent are as follows:
\(\sin(\theta) = \dfrac{\text{opposite side}}{\text{hypotenuse side}}\)

\(\tan(\theta) = \dfrac{\text{opposite side}}{\text{adjacent side}}\)

Answer 9

So in this case, \(\theta = y\), the opposite side is \(a\), the hypotenuse side is \(6\) and the adjacent side is \(b\):

Answer 10

All we have to do now is write the expression that represents \(\cos(y^{\circ})\). @dancingdancer, Do you remember the ratio for cosine?

Answer 11

is it b over 6?

Answer 12

Indeed it is.

Answer 13

Correct.

Answer 14

awesome, thank you!

Answer 15

You're welcome