Question

7.) Find the area of the given figure.

Answer 1

g

Answer 2

\[A_{sc} = \pi r^2\]
Area of a semicircle is equal to pi times radius squared

\[A_{r} = l \times w\]
Area of a rectangle/square is equal to length times width.

Answer 3

Notice how the shapes can all be broken down into semicircles and rectangles. Solve for each shape then add them up.

Answer 4

In some instances they only give you the diameter. So divide it by 2 to get the radius

d = 2r

Answer 5

\[A_{t} = \frac{ 1 }{ 2 }bh\]

Area of a triangle equals 1/2 times base times height

Answer 6

Asc = area of a semicircle

Answer 7

At = area of a triangle

Answer 8

1

Answer 9

U can break them into 2 if u want

Answer 10

I can check ur answers in like 20min xd sorry

Answer 11

Semicircle I got 201

Answer 12

For 7

Answer 13

@Katy

Answer 14

Technically yes. We didn't get the same value because you used less of the pi numbers after the decimal.

Answer 15

\[A_{sc} = \pi r^2 = \pi(8)^2 = 201.06\]

Answer 16

.14 are the first two values after the decimal point. There's a lot more. I used my calculator which has the pi symbol, which uses more numbers probably.

Answer 17

If your teacher used 3.14 in class then you're probably fine.

Answer 18

Yes

Answer 19

Yes

Answer 20

Yes

Answer 21

Yeah, what option do you think it is?

Answer 22

mhm

Answer 23

Affirmative, haha

Answer 24

Affirmative = yes

Answer 25

There's two semicircles, but since two semicircles is one semicircle (and they share the same rectangle inbetween them, thus the same diameter, you can use the formula for one circle, or just multiple the semicircle result by 2

Answer 26

Hmm, good thing we had this question actually. I copied and pasted the wrong formula for the semicircle
\[A_{c} = \pi r ^2\]
\[A_{sc} = \frac{ \pi r^2 }{ 2 }\]

Answer 27

So for 7, it's actually B, since you divide 201 by 2

Answer 28

Yeah

Answer 29

Lol this is what I get for helping w/math at 1am :^)

Answer 30

Should be fine now though lol

Answer 31

I live in Hawaii, so HST (Hawaiian Standard Time)

Answer 32

So for #8, since it's two semicircles, or one full circle, plus a rectangle, you can do:

\[A_{c} = \pi(7.5)^2 \]
+
\[A_{r} = 25 \times 15 \]

Answer 33

Yes

Answer 34

Yes

Answer 35

Affirmative

Answer 36

Oh just use \(\color{#0cbb34}{\text{Originally Posted by}}\) @Shadow
Hmm, good thing we had this question actually. I copied and pasted the wrong formula for the semicircle
\[A_{c} = \pi r ^2\]
\[A_{sc} = \frac{ \pi r^2 }{ 2 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 37

2nd formula

Answer 38

Yes

Answer 39

Yes x2

Answer 40

Times 2, as in saying it for the second time. Don't mind it xd

Answer 41

Well that's the triangle, so we just add that to the semicircle result.

Answer 42

Yes

Answer 43

Yes, we have a semicircle and a square.

Answer 44

Yes

Answer 45

Ik you got this last part. I believe.

Answer 46

Yes

Answer 47

Yes

Answer 48

Yeah it's looking like E

Answer 49

Hey Katy that's it for now right. My pillow is calling me c;

Answer 50

It seems like the asker deleted all of his/her original posts, so it looks like you were responding to yourself lol