Question

g

Answer 1

i think so

Answer 2

sure

Answer 3

hold on im trying to answer them

Answer 4

area of parallelogram = base * height

Answer 5

area of trapezium = 1/2 * dist between the parallel sides * (sum of lengths of parallel sides)

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Katy
12*9=108
\(\color{#0cbb34}{\text{End of Quote}}\)
??

Answer 7

you're supposed to calculate their volume and area respectively

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty
the volume of cylinder = \(2\pi rh\)
or you could also say: volume of cylinder = area of circular base * height
\(\color{#0cbb34}{\text{End of Quote}}\)
typo
it's supposed to be \(Volume = \pi \times r^2 \times h\)

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Katy
A) 718π cm3
B) 1444π cm3
C) 972π cm3
D) 1347π cm3
\(\color{#0cbb34}{\text{End of Quote}}\)
are these your options?

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Katy
Find the volume of the figure.
I forgot to add that to the question that we are solving.
\(\color{#0cbb34}{\text{End of Quote}}\)
you don't have to add this, it's clear from the options that we're supposed to find the volume as the units are \(cm^3\)

Answer 11

anyways, use this \(Volume = \pi \times r^2 \times h\)

Answer 12

yes

Answer 13

Because you can't find it in the options?

Answer 14

well, it's there in the options

Answer 15

\(718\color{red}\pi\)
\(1444\color{red}\pi\)
\(972\color{red}\pi\)
\(1347\color{red}\pi\)

Answer 16

yup

Answer 17

C) 972π cm3?

Answer 18

duh

Answer 19

\(\color{red}{\pi} \times 9^2 \times 12 = 972 \color{red}\pi\)

Answer 20

\(\href{https://lmgtfy.com/?q=how+to+find+the+area+of+a+segment+of+a+circle}{:)}\)

Answer 21

0/2 ??

Answer 22

\(\Huge \theta \ne 0\)

Answer 23

\(\theta\) is the angle in radians

Answer 24

I'll simplify it for you

A circle covers \(360^o\) degrees or \(2\pi\) radians.
\(\pi \times r^2\) is the area of a circle covering all \(360 ^o\) degrees.

The area of a segment covering \(1^o\) would be \(\large \frac{\pi r^2}{360}\)
area of segment covering \(x^o\)would be \(\Large\frac{\pi r^2}{360} \times x\)

Answer 25

no.

Answer 26

you just have to plug in the values

Answer 27

what is the radius \(\left(r\right)\) and the angle of segment \(\left( x \right)\) in your question?

Answer 28

no. check the question again

Answer 29

yes.

Answer 30

bruh

Answer 31

if you're unable to plug in the values, I'd recommend that you should watch a video explanation of this on youtube

Answer 32

no

Answer 33

\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty
I'll simplify it for you

A circle covers \(360^o\) degrees or \(2\pi\) radians.
\(\pi \times r^2\) is the area of a circle covering all \(360 ^o\) degrees.

The area of a segment covering \(1^o\) would be \(\large \frac{\pi r^2}{360}\)
area of segment covering \(x^o\)would be \(\Large\frac{\pi r^2}{360} \times x\)
\(\color{#0cbb34}{\text{End of Quote}}\)
use this instead

Answer 34

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Katy
(2*3.14)*3.14*(6^2)/360
\(\color{#0cbb34}{\text{End of Quote}}\)
wheres the \(\theta\)??

Answer 35

when did i say that?

Answer 36

\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty
I'll simplify it for you

A circle covers \(360^o\) degrees or \(2\pi\) radians.
\(\pi \times r^2\) is the area of a circle covering all \(360 ^o\) degrees.

The area of a segment covering \(1^o\) would be \(\large \frac{\pi r^2}{360}\)
area of segment covering \(x^o\)would be \(\Large\frac{\pi r^2}{360} \times x\)
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 37

see the formula at the end of this^ ? use that

Answer 38

yes.

Answer 39

C) 6π cm2?

Answer 40

yeah

Answer 41

post them

Answer 42

You have to Rewrite the question each time.
Once a question is answered you have to close it and open a new question.