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Can somebody explain how to do part b for this?
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apologies in advance for my calculus being rusty but I believe you would just write |dw:1588694677399:dw| f(x) = f(x0) + f'(x0)(x-x0) + [ f''(x0)(x-x0)^2 ] / 2! using the appropriate values from the table
for the approximation you'd just plug in x = 0.2 into the polynomial you just wrote and evaluate
I'm not super confident so I'm going to tag @imqwerty to look over this as well
Nvm I figured it out, all I had to do was plug in x^3 into the taylor polynomial to get \[4 + 5x ^{3} - (x ^{3})^{2}/2!\] Then differentiate it twice to get \[15x ^{2}-3x ^{5}\] Thanks for the help though!
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