Question

Is the product of 42*63 over or under 2,400?
Use what you know about place value in the standard algorithm to explain your answer.

Use 1,2,3,4,5 to make the multiplication problem with the greatest product?
How does the placement of the numbers impact the product?

Answer 1

i already know the answer to the first part of the question. i just need help with the second part

Answer 2

it will be over cause 42*63 = 2,646

Answer 3

i know that answer

Answer 4

just need help with the second part where it tells me to “ Use 1,2,3,4,5 to make the multiplication problem with the greatest product?
How does the placement of the numbers impact the product?”

Answer 5

Well we aren't allowed to give you an exact answer though I will try and help you best I can

Answer 6

I didn't kitty did lol I'm a good boy

Answer 7

nu u aint

Answer 8

Yes I am anyway hmmm

Answer 9

TBH, I don't think the placement of the numbers will affect it at all

Answer 10

i just need the answer to the second part

Answer 11

No matter what you do your gonna get 120

Answer 12

Hope that helps!

Answer 13

im not sure that’s correct but ok

Answer 14

Ask Mercury he's the math dude my thing is English lol

Answer 15

ok thanks for the help tho

Answer 16

Anytime I'm happy to help

Answer 17

Here comes Mercury to save the day

Answer 18

XD

Answer 19

this is a complicated problem and I'm not 100% sure of my reasoning, but here's my attempt:

I interpreted the problem as making a multiplication problem using the given digits 1,2,3,4 and 5 to create new numbers to be used in the product: ex: 1234*5, 123*45, etc.

with that being said, I had a hunch that, in order to maximize the product, you would need to create a 3 digit * 2 digit problem in order to maximize the number of digits being multiplied. for example, I compared 4321*5 with 531*42 and found that the second product is larger.

now, with that in mind, I wanted a setup that would put larger digits in the hundreds/tens places rather than the ones places (ex: I theorized that 543 * 21 would be greater than, say, 321*45). so I *thought* that 543*21 would be the greatest product but I found that different arrangements ended up with greater products.

so, my next line of reasoning: the tens digit of the 2-digit number gets multiplied with all three digits of the three-digit number (confirm this yourself by multiplying a 3 digit * 2 digit number), so I should make the two digit number start with 5, and the three-digit number start with 4

now, since the ones place digit of the two-digit number also gets multiplied to every three-digit number, I wanted to maximize that digit as well, so I ended up with 52 as the two digit number.

putting the remaining digits in the three-digit number (3 and 2) I put the 3 in the tens place and the 2 in the ones place (since 3 is bigger than 2, I want 3 in the tens place to maximize the product. 32 is bigger than 23 after all.)

my solution: 431*52

Answer 20

@dude @thesmartone sorry if this is a lot but would you mind checking my work

Answer 21

See Mercury saves the day XD

Answer 22

wow... thank u soo much man!

Answer 23

that’s a lot. you didn’t have to do all that. i truly appreciate it a lot tho

Answer 24

Brilliant deductions, I probably wouldn't have figured that all out on my own. But
I concur, that would indeed be the greatest product of those numbers