Ask your own question, for FREE!
Mathematics 20 Online
MiraAngel:

After two six-sided dice are rolled, what is the probability that the dice faces add up to either a 4 or 6?

Aqual:

1&3,2&2,1&5,2&4,3&3

Aqual:

so 5 chances

Aqual:

now u need to find probability

Aqual:

5/12 = probability

Aqual:

@Salmon

Aqual:

Is that right?

Salmon:

If we were to get statistical then no, but I do believe you are correct Aqual

Aqual:

kk

Aqual:

thx

jhonyy9:

so there are two dice with six-six sides yes ?

Aqual:

yes

jhonyy9:

and the question is what is the probability to add up to 4 or 6 so how many sides are two dice total ?

MiraAngel:

12

jhonyy9:

yes 12 and on these two dice how much is the 4th and 6th sides total ?

MiraAngel:

10?

MiraAngel:

There are 5 combinations of the two that could make up 3 and 6...

Aqual:

4 qnd 6

Aqual:

so divide 5 by 12

MiraAngel:

yeah lol

jhonyy9:

on one dice there is one 4th side and one 6th side so on two dice

MiraAngel:

there are 2 4th sides and 2 6th sides

MiraAngel:

right?

jhonyy9:

yes

MiraAngel:

ok. So I am understanding little pieces of this problem but I am still a little confused. lol

jhonyy9:

why ? there are 12 sides with probability to add 4 or 6 two time so this is 2+2 =4 4 from 12 so how much ?

MiraAngel:

1/3?

jhonyy9:

perfectly

jhonyy9:

do you understand the way now ?

MiraAngel:

Yes, I think so! May I send a couple more problems to see if I can get the hang of it a little more?

jhonyy9:

- so i think just you need try use this way what above used and try solve them in this way

MiraAngel:

Okay. There are different problems tho. Does this type of equation work to help solve them all?

jhonyy9:

not really at all - depend what style of cases are there

MiraAngel:

oh okay

ashyboy007:

5/36?! 🤔

ashyboy007:

36 combination with 5 chances?! Idk

MiraAngel:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 not really at all - depend what style of cases are there \(\color{#0cbb34}{\text{End of Quote}}\) wait... it says how many different combinations can you use to add up to 4 and 6 tho so it wouldn't just be four would it?

MiraAngel:

I need helpppppppppp! lol I am so confusedddddddddddd!

imqwerty:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MiraAngel I need helpppppppppp! lol I am so confusedddddddddddd! \(\color{#0cbb34}{\text{End of Quote}}\) Whats confusing u

emilybethch:

f the first number is a 1, then there is a 1 in 6 chance that it would total 4 (1 plus 3) If the first number is 2, then there is a 1 in 6 chance that it would total 4 (2 plus 2) If the first number is 3, then there is a 1 in 6 chance that it would total 4 (3 plus 1) If the first number is 4–6, then it cannot total 4. Out of a total 36 possibilities, the following possibilities would equal 4 1, then 3 2, then 2 3, then 1 So, there is a 3 out of 36 chance that the sum of the two dice rolled would equal 4 When we simplify, it is a 1 in 12 chance. But, why is it 1 in 12? For the first die, it could equal one of 3 numbers, out of a 6 sided die, so it is a 1 in 2 chance. For the second die, however, it could only equal one possible number, given that the first die rolled 1–3 The second die has a 1 in 6 chance of totaling 4. When we multiply the chances [Math Processing Error] Then it would give [Math Processing Error]or 1 in 12. (I got dis off of Quora)

MiraAngel:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @emilybethch f the first number is a 1, then there is a 1 in 6 chance that it would total 4 (1 plus 3) If the first number is 2, then there is a 1 in 6 chance that it would total 4 (2 plus 2) If the first number is 3, then there is a 1 in 6 chance that it would total 4 (3 plus 1) If the first number is 4–6, then it cannot total 4. Out of a total 36 possibilities, the following possibilities would equal 4 1, then 3 2, then 2 3, then 1 So, there is a 3 out of 36 chance that the sum of the two dice rolled would equal 4 When we simplify, it is a 1 in 12 chance. But, why is it 1 in 12? For the first die, it could equal one of 3 numbers, out of a 6 sided die, so it is a 1 in 2 chance. For the second die, however, it could only equal one possible number, given that the first die rolled 1–3 The second die has a 1 in 6 chance of totaling 4. When we multiply the chances [Math Processing Error] Then it would give [Math Processing Error]or 1 in 12. (I got dis off of Quora) \(\color{#0cbb34}{\text{End of Quote}}\) thank you!

MiraAngel:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty \(\color{#0cbb34}{\text{Originally Posted by}}\) @MiraAngel I need helpppppppppp! lol I am so confusedddddddddddd! \(\color{#0cbb34}{\text{End of Quote}}\) Whats confusing u \(\color{#0cbb34}{\text{End of Quote}}\) I think I got it... lol idk I'll see...

imqwerty:

Aight

MiraAngel:

thx! alla y'all!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!