6(4)^2x+8 is rewritten as 6(r)^x+4. What is the value of r?
@Hero
\(6(4)^{2x+8} = 6(r)^{x+4}\) ?
Yep
Well, what happens if you factor out 2 from 2x + 8?
Even clearer if you divide out the 6 first on both sides.
x+8?
So 6 is gone from both sides
If you divide out the 6 on both sides you end up with \( 4^{2x+8}=r^{x+4}\)
Yes
So from there you would factor out the 2 from 2x + 8
How
Question: What happens if you apply the distributive rule to 3(x + 2) ?
Rainbow multiply?
Never heard of that, but what result do you get if you apply the distributive rule?
3x+6?
Correct, now what happens if you reverse that process you just performed?
Reverse how
By factoring.
Omg how do I factor
I gave you 3(x + 2). You performed the distributive rule to get 3x + 6.
Right, rainbow method
You got to that result by multiplying the x and the 2 by three.
What is the inverse of multiplication?
Division
exactly
What do I divide
So when you factor, you're performing division.
Right
You divide 3x + 6 by 3 and then you write the result of that, then put the divisor on the outside of the parentheses.
It's just 6
So when you divide 3x+6 by 3, the result is x + 2. And then you put the three on the outside of the parentheses.
!
So you write 3(x + 2) which is what we started with.
Ok
What was the point of just going back to where we started?
To show you how to factor
Ok
You asked "how do you factor"
Ok now the actual doing of the problem
That requires factoring 2x + 8
Which requires knowing how to factor
2(x+4)
Congratulations. You did it.
Thanks to you. Now what?
I just hope you did it on your own strength.
Now you have: \(4^{2(x+4)}=r^{x+4} \)
You don't need strength to divide
Yes
Now it looks like we might be able to say what r is
16?
Correct
Wow how easy
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