Question

Math... again. :)

Answer 1

not soppused to say this but uhm have you tried using mathway it'll give you the answer and the explanation on how the answer was found

Answer 2

y do you think she would ask on this site then... Anyways Ill give you an explanation : )

Answer 3

no lol I have a lot of these kinds of questions so I'm tryna kinda get the hang of the problems so that I can work out the others

Answer 4

okay. thx!

Answer 5

so lets get a picture of the unit circle.

Answer 6

Now if we look at the unit circle, remember that cos are x values. So there are 2 points with an x value of \[\cos^{-1} -(\sqrt{3}/2)\]
Referencing the unit circle, we can see that these points are \[((-\sqrt{3}/2), (1/2)\]and
\[((-\sqrt{3}/2), (-1/2)\]

At these points, the radian measures are \[5\pi/6 \] and
\[7\pi/6\]

Answer 7

So all in all, if you want to find the radian measure of a specific value such as what we had, find all points on which that x value (cos) or y value (sin) lie. What I mean by that is if we have the inverse cosine of some coordinate, we need to find all occurrences of where that coordinate is and then find the angle of that point.

Answer 8

lmk if you don't get anything or need further explanation. Have a good day. :)

Answer 9

Thank u so much!

Answer 10

np