A rubber ball dropped on a hard surface takes a sequence of bounces, each one 3/5 as high as the preceding one. If this ball is dropped from a height of 10 feet, what is the total vertical distance it has traveled after it hits the surface the 5th time?
Welcome to QC! Can you provide the answer choices?
-46 14/125 -36 14/125 -43 111/125 -23 7/125
Thanx, so what do u think the answer is?
I'm not sure, maybe the last one?
So we have, a rubber ball dropped on a hard surface takes a sequence of bounces, each one 1/6 as high as the preceding one.
to figure out If this ball is dropped from a height of 12 feet, how far will it have traveled when it hits the surface the fifth time.
once the ball is dropped on hard surface it bounces 1/6 of preceding one and comes down the same distance.
So basically.
When the ball is dropped from 12 feet height
after first hit = 12x 1/6 up +12 x 1/6 down = 4
Is this making sense so far?
kinda yea
now what?
Ok so, new height= 12x 1/6=2feet
so we went from the height of 10 to the height of 12?
I believe so
okay, im following
Wait now im confused 🤔
i was confused too, because it said "from a height of 10 feet" and you went on talking about 12 feet, which lost me
ya im confusing myself here
i was just confused on how you went from 10 feet to 12 feet
same, I think I got my math wrong
lol it's okay, it happens
do you still understand on how to do the problem?
I think ya
howd up
okay
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