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Mathematics 16 Online
hiya:

@563blackghost

hiya:

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563blackghost:

Have you simplified the equation already? Multiply `x+5` to each part of the equation so we can rid of fractions. \(\bf{(\frac{5}{x+5} \times (x+5)) = (4 \times(x+5)) - (\frac{x}{x+5} \times (x+5))}\) What did you simplify down from that equation?

hiya:

this is the remaining afte simplifying the x+5 5=4x+5-x i this right?

563blackghost:

yup thats correct. Now simplify it even further till you get an answer to x. What did u get?

hiya:

0?

563blackghost:

Well.. \(\bf{5 = 4(x + 5) - x}\) Simplify. \(\bf{5=4x +20 - x}\) Combine. \(\bf{5 = 3x + 20}\) Simplify further, what would `x` be?

hiya:

-15/3?

563blackghost:

yup but -15 divided by 3 is what?

hiya:

-5

hiya:

@563blackghost am I right?

563blackghost:

yes, but you need to verify the solution to the equation, to see if it stands true.

hiya:

oh how do i do that?

hiya:

@563blackghost

563blackghost:

u set one side of your equation to equal to `0`, which you then plug in your solution of x to find if it is actually equal to `0`. If it does it's a true solution, if not its extraneous.

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