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Mathematics 13 Online
Marsden:

Please help me with my math problem.

Marsden:

Marsden:

I know the answer, because I have the answer key, but I do not know how to get there.

jhonyy9:

so how you see there on this posted attached image there are two parallele lines intersected by a transversal line - for you can solve your posted problem you need to know the theorems of alternate internal/external angles do you know these ?

xxcoffee:

i would help buttt i aint got my note book rn cuz im not in school till tmr

Marsden:

yes, i know when two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent . And when two parallel lines are cut by a transversal , the resulting alternate exterior angles are congruent .

jhonyy9:

ok in this image what are congruent angles ? what you can use to solve the problem

Marsden:

I don't know, Im sorry

jhonyy9:

ok i gtg. - sorry - but i will come back in a few moments - i will explain it to you -

Marsden:

ok

jhonyy9:

hi nobody dont helped again here on this ???

Laylalyssa:

I dont know how to do it

jhonyy9:

using the alternate interior -exterior angles congruentcy

jhonyy9:

using these <BCD = <CDE yes ?

Laylalyssa:

..yes

jhonyy9:

<EDF = <CBD yes ?

Laylalyssa:

I think yes

jhonyy9:

<ABD + >EDF + <CDE = 180° yes ?

jhonyy9:

sorry <EDF

Laylalyssa:

oh ya @marsden

jhonyy9:

@Laylalyssa do you understand it now ?

Laylalyssa:

kind of yes

jhonyy9:

<BCD +<ABD + <EDF = 180° and from this equation plus this above wrote equation you can calcule the x value

jhonyy9:

<ABD + >EDF + <CDE = 180° <BCD +<ABD + <EDF = 180°

jhonyy9:

from these result <CDE = <BCD yes ?

Laylalyssa:

yes yes

jhonyy9:

<ABD = 3x +4 <BCD = 6x -8 <EDF = 7x -20 <ABD + >EDF + <CDE = 180° <BCD +<ABD + <EDF = 180° <CDE = <BCD

Laylalyssa:

oh

jhonyy9:

3x +4 + 7x -20 + 6x -8 = 180 6x -8 + 3x +4 + 7x -20 = 180 solve one equation for x

jhonyy9:

16x -24 = 180 16x = 204 x = 204/16 = ?

darkknight:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 using these <BCD = <CDE yes ? \(\color{#0cbb34}{\text{End of Quote}}\) how?

jhonyy9:

opposite angles on the other side

jhonyy9:

@darkknight ok ?

darkknight:

yeah yeah my b

Laylalyssa:

3x+4+7x−20+6x−8=180 3x+4+7x+−20+6x+−8=180 then to do the like terms thing.. (3x+7x+6x)+(4+−20+−8)=180 16x+−24=180 16x−24=180 16x−24+24=180+24 16x=204 16x/16=104/16 so then would it be x=51/4 ? right or no

jhonyy9:

yes x = 12,75

Laylalyssa:

oh ok

jhonyy9:

and now ?

jhonyy9:

<BCD = 6x -8 <BCD = ?

jhonyy9:

questions ?

darkknight:

no, just plug in the value of x into the expression for angle BCD to find the angle measure. Good job Jhonyy and Layla

Laylalyssa:

thanx

jhonyy9:

ty

jhonyy9:

and ty @Laylalyssa for your collaboration

Laylalyssa:

np

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