Please help me with my math problem.
I know the answer, because I have the answer key, but I do not know how to get there.
so how you see there on this posted attached image there are two parallele lines intersected by a transversal line - for you can solve your posted problem you need to know the theorems of alternate internal/external angles do you know these ?
i would help buttt i aint got my note book rn cuz im not in school till tmr
yes, i know when two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent . And when two parallel lines are cut by a transversal , the resulting alternate exterior angles are congruent .
ok in this image what are congruent angles ? what you can use to solve the problem
I don't know, Im sorry
ok i gtg. - sorry - but i will come back in a few moments - i will explain it to you -
ok
hi nobody dont helped again here on this ???
I dont know how to do it
using the alternate interior -exterior angles congruentcy
using these <BCD = <CDE yes ?
..yes
<EDF = <CBD yes ?
I think yes
<ABD + >EDF + <CDE = 180° yes ?
sorry <EDF
oh ya @marsden
@Laylalyssa do you understand it now ?
kind of yes
<BCD +<ABD + <EDF = 180° and from this equation plus this above wrote equation you can calcule the x value
<ABD + >EDF + <CDE = 180° <BCD +<ABD + <EDF = 180°
from these result <CDE = <BCD yes ?
yes yes
<ABD = 3x +4 <BCD = 6x -8 <EDF = 7x -20 <ABD + >EDF + <CDE = 180° <BCD +<ABD + <EDF = 180° <CDE = <BCD
oh
3x +4 + 7x -20 + 6x -8 = 180 6x -8 + 3x +4 + 7x -20 = 180 solve one equation for x
16x -24 = 180 16x = 204 x = 204/16 = ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 using these <BCD = <CDE yes ? \(\color{#0cbb34}{\text{End of Quote}}\) how?
opposite angles on the other side
@darkknight ok ?
yeah yeah my b
3x+4+7x−20+6x−8=180 3x+4+7x+−20+6x+−8=180 then to do the like terms thing.. (3x+7x+6x)+(4+−20+−8)=180 16x+−24=180 16x−24=180 16x−24+24=180+24 16x=204 16x/16=104/16 so then would it be x=51/4 ? right or no
yes x = 12,75
oh ok
and now ?
<BCD = 6x -8 <BCD = ?
questions ?
no, just plug in the value of x into the expression for angle BCD to find the angle measure. Good job Jhonyy and Layla
thanx
ty
and ty @Laylalyssa for your collaboration
np
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