Question

help pls

Answer 1

What's your question?

Answer 2

with 1

Answer 3

I believe the pointer gets larger, since the middle beam is the largest (the middle beam is the largest, the far beam of medium size, and the front beam the smallest.).

Answer 4

Actually I believe the pointer goes down.

Answer 5

and 2

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @justus
Actually I believe the pointer goes down.
\(\color{#0cbb34}{\text{End of Quote}}\)
Explanation is that In order for the weight to be right, the pointer must be below or inside the relation (zero).

Answer 7

both answers ^^

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @JollyRanchers45
both answers ^^
\(\color{#0cbb34}{\text{End of Quote}}\)
how u get that

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @janiya101
and 2
\(\color{#0cbb34}{\text{End of Quote}}\)
Things with a weight larger than 300 g leave the pointer below the reference and must be finished in order to meet the correct weight with the other two arms.

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @janiya101
\(\color{#0cbb34}{\text{Originally Posted by}}\) @JollyRanchers45
both answers ^^
\(\color{#0cbb34}{\text{End of Quote}}\)
how u get that
\(\color{#0cbb34}{\text{End of Quote}}\)



looked them up plus I took this already lol

Answer 11

ok

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @justus
\(\color{#0cbb34}{\text{Originally Posted by}}\) @janiya101
and 2
\(\color{#0cbb34}{\text{End of Quote}}\)
Things with a weight larger than 300 g leave the pointer below the reference and must be finished in order to meet the correct weight with the other two arms.
\(\color{#0cbb34}{\text{End of Quote}}\)
@janiya101 Did you understand?

Answer 13

yes

Answer 14

Good

Answer 15

thx

Answer 16

NP