Question

5(2x − 3) = 5

Part A: How many solutions does this equation have?

Part B: What are the solutions to this equation? Show your work.

Answer 1

10x -15 = 5
10x = 20
x = 2
only one soultion so it would be x = 2

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @CocoCammron
10x -15 = 5
10x = 20
x = 2
only one soultion so it would be x = 2
\(\color{#0cbb34}{\text{End of Quote}}\)
brainly

Answer 3

The first thing you have to do is distribute ,
\(5(2x−3)=5\)
\((5)(2x)+(5)(−3)=5\)
\(10x+−15=5\)
\(10x−15=5\)

Then we have to do \(+15\) to both of the sides (`-15` and we need the opposite)
\(10x−15+15=5+15\)
\(10x=20\)

Then we divide by 10, to both of the sides (it says `10x`)
\(\LARGE\frac{10x}{10}=\frac{20}{10}\)
\(\frac{10x}{10}\) cancels so all you have left is \(\frac{20}{10}\)
Simplify it, and then you'll have your answer.

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @carmelle
\(\color{#0cbb34}{\text{Originally Posted by}}\) @CocoCammron
10x -15 = 5
10x = 20
x = 2
only one soultion so it would be x = 2
\(\color{#0cbb34}{\text{End of Quote}}\)
brainly
\(\color{#0cbb34}{\text{End of Quote}}\)
OK first of all I put this in my own wordssssssss

Answer 5

Distribute
5(2𝑥−3)=5
10𝑥−15=5

Add 15 to both sides of the equation
10𝑥−15=5
10𝑥−15+15=5+15

add the numbers
10𝑥=20

Divide both sides of the equation by the same term
10𝑥=20
10𝑥/10=20/10

Cancel terms that are in both the numerator and denominator
Divide the numbers
𝑥=2

Solution
𝑥=2

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @CocoCammron
\(\color{#0cbb34}{\text{Originally Posted by}}\) @carmelle
\(\color{#0cbb34}{\text{Originally Posted by}}\) @CocoCammron
10x -15 = 5
10x = 20
x = 2
only one soultion so it would be x = 2
\(\color{#0cbb34}{\text{End of Quote}}\)
brainly
\(\color{#0cbb34}{\text{End of Quote}}\)
OK first of all I put this in my own wordssssssss
\(\color{#0cbb34}{\text{End of Quote}}\)
The whole first part was copied word for word but ok..

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @carmelle
\(\color{#0cbb34}{\text{Originally Posted by}}\) @CocoCammron
\(\color{#0cbb34}{\text{Originally Posted by}}\) @carmelle
\(\color{#0cbb34}{\text{Originally Posted by}}\) @CocoCammron
10x -15 = 5
10x = 20
x = 2
only one soultion so it would be x = 2
\(\color{#0cbb34}{\text{End of Quote}}\)
brainly
\(\color{#0cbb34}{\text{End of Quote}}\)
OK first of all I put this in my own wordssssssss
\(\color{#0cbb34}{\text{End of Quote}}\)
The whole first part was copied word for word but ok..
\(\color{#0cbb34}{\text{End of Quote}}\)
You're still not allowed to do that
js

Answer 8

O.o

Answer 9

do this in your dms plz

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jaedengome
do this in your dms plz
\(\color{#0cbb34}{\text{End of Quote}}\)
we aren't getting off topic

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jaedengome
do this in your dms plz
\(\color{#0cbb34}{\text{End of Quote}}\)
We're talking about the work
Why would be talk about solving the problem in the DM's?
Now lets shut up before this gets off-topic and turns into spam.

Answer 12

thx guys for your help.

Answer 13

np