5x-7x+6=-2(x-3) A.) 0 B.) 3/4 C.) 2 D.) infinitely many solutions
hmm?
5x - 7x + 6 = -2(x - 3) Distribute the -2 5x - 7x + 6 = -2x + 6 Combine like terms on the left side -2x + 6 = -2x + 6 Add 2x to both sides 6 = 6 so d
1: Simplify both sides of the equation. 5x−7x+6=−2(x−3) 5x+−7x+6=(−2)(x)+(−2)(−3)(Distribute) 5x+−7x+6=−2x+6 (5x+−7x)+(6)=−2x+6(Combine Like Terms) −2x+6=−2x+6 −2x+6=−2x+6 2: Add 2x to both sides. −2x+6+2x=−2x+6+2x 6=6 3: Subtract 6 from both sides. 6−6=6−6 0=0 All real numbers are solutions.
So the first step would be to distribute \(5x−7x+6=−2(x−3)\) \(5x+−7x+6=(−2)(x)+(−2)(−3)\) \(5x+−7x+6=−2x+6\) Then combine like terms \((5x+−7x)+(6)=−2x+6\) \(−2x+6=−2x+6\) Then take \(2x\) add it to both sides of the equation \(−2x+6+2x=−2x+6+2x\) \(=6=6\) Subtract 6 from both sides of the equation \(6−6=6−6\)
No direct answers smh.
yh np,
\(\color{#0cbb34}{\text{Originally Posted by}}\) @sxdsouls yh np, \(\color{#0cbb34}{\text{End of Quote}}\) Wait I don't see a 6 there
There's No 6 there so can you explain that
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Lilian9667 \(\color{#0cbb34}{\text{Originally Posted by}}\) @sxdsouls yh np, \(\color{#0cbb34}{\text{End of Quote}}\) Wait I don't see a 6 there \(\color{#0cbb34}{\text{End of Quote}}\) 2: Add 2x to both sides. −2x+6+2x=−2x+6+2x 6=6 3: Subtract 6 from both sides. 6−6=6−6 0=0
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie So the first step would be to distribute \(5x−7x+6=−2(x−3)\) \(5x+−7x+6=(−2)(x)+(−2)(−3)\) \(5x+−7x+6=−2x+6\) Then combine like terms \((5x+−7x)+(6)=−2x+6\) \(−2x+6=−2x+6\) Then take \(2x\) add it to both sides of the equation \(−2x+6+2x=−2x+6+2x\) \(=6=6\) Subtract 6 from both sides of the equation \(6−6=6−6\) \(\color{#0cbb34}{\text{End of Quote}}\) most likely what he said i guess
ok
got it ?
yup
mk
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