Solve -4b + 2 = 18. b =
simple algebra
i am not good algebra
ok first subtract 2 from both sides, it will leave you with -4b=16. then divide both sides by -4 and you get b= -16/4 or -4
\(\color{#0cbb34}{\text{Originally Posted by}}\) @bemine11 i am not good algebra \(\color{#0cbb34}{\text{End of Quote}}\) what is 4 times 4?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @simsharrison \(\color{#0cbb34}{\text{Originally Posted by}}\) @bemine11 i am not good algebra \(\color{#0cbb34}{\text{End of Quote}}\) what is 4 times 4? \(\color{#0cbb34}{\text{End of Quote}}\) 16
so b= -4
ok -4 times -4? = 16 so b=-4
yup
So the first step is to change the plus to a minus -4b - 2 = 18 subtract 2 from both sides of the equation, \(−4b+2−2=18−2\) Which equals −4b=16 So then divide both sides -4 \(\LARGE\frac{-4b}{-4}=\frac{16}{-4}\) \(\cancel{\color{red}{\LARGE\frac{-4b}{-4}}}=\frac{16}{-4}\) So \(\frac{-4b}{-4}\) cancels all you have left is \(\frac{16}{-4}\) simplify that then you have your answer.
thx @supie
np
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