Question

The angles below are supplementary. What is the value of x? (1 point)

A pair of supplementary angles is shown. One angle measures 6x plus 48 degrees, and the other angle measures 60 degrees.
2
7
12
18

Answer 1

Supplementary= adding up to 180 degrees

6x+48+60=180
6x+108=180
-108 -108
6x=72
6x/6 = 72/6
x=12

Answer 2

thanks

Answer 3

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
thanks
\(\color{#0cbb34}{\text{End of Quote}}\)
Happy to help! :)

Answer 4

get some sleep tho lol its 12:30 where i am and u shouldnt be doing work at that kinda time

Answer 5

i kno but me i always wanna stay ahead of my work this semesiter for i wont fail

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
i kno but me i always wanna stay ahead of my work this semesiter for i wont fail
\(\color{#0cbb34}{\text{End of Quote}}\)
yeah ik me too but like u can do this in the morning lol

Answer 7

true:)

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
true:)
\(\color{#0cbb34}{\text{End of Quote}}\)
Yess so gts now dude 😂

Answer 9

but if i need help with anything else u mind if i hit u up

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
but if i need help with anything else u mind if i hit u up
\(\color{#0cbb34}{\text{End of Quote}}\)
Nah go right on ahead hit me up at @Devum or @Convert which is my other account and ill try to get back to u asap

Answer 11

im not goin to sleep until i get these three questions done

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
im not goin to sleep until i get these three questions done
\(\color{#0cbb34}{\text{End of Quote}}\)
Alright well if you need help with anyone jus let me know lol

Answer 13

u mind helping me with these three questions tho u just be confused sometimes and get stress out easily

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
u mind helping me with these three questions tho u just be confused sometimes and get stress out easily
\(\color{#0cbb34}{\text{End of Quote}}\)
Yeah ofc dude jus post em

Answer 15

ok

Answer 16

A running track in the shape of an oval is shown. The ends of the track form semicircles.

A running track is shown. The left and right edges of the track are identical semicircles. The top and bottom edges of the track are straight lines. The track has width 42 m and length of one straight edge 110 m.
What is the perimeter of the inside of the track? (π = 3.14) (1 point)

304.00 m
351.88 m
912.37 m
1,604.74 m

Answer 17

if u need the picture instead ill try to give it to u

Answer 18

Yeah the picture wouldn help lol

Answer 19

k

Answer 20

Thx dude I appreciate it

Answer 21

np but im trying to put the sc on here but its hard

Answer 22

sorry if im taking long

Answer 23

Ohh okay I see so 1st you find the perimeter of a rectangle so 2L*2W L being length and W being width

Answer 24

Then the circumference is 2*the diameter then multiply that times pi

Answer 25

ok give me a sec

Answer 26

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
ok give me a sec
\(\color{#0cbb34}{\text{End of Quote}}\)
Alright

Answer 27

And the 2 halfs on the end make a full circle btw lol

Answer 28

ok im confused and gettting stress out and i kno im taking up some much of your time so u dont gotta help me

Answer 29

Nooo I'll help you

Answer 30

Here I'll give you a step by step answer hold up though I'm doing my own hw but I'm almost done

Answer 31

ok

Answer 32

Okay so now you see we have 42 and 110 as our sides:

2*42+2*110=304

Now we have the perimeter of the square, but we need to subtract the 2, 42 sides because it does not border the side.

304-2*42=220

Now that we have that we need to find the circumference (perimeter) of a circle:
The formula is diameter*pi:

42*3.14=131.88

Now that we have to circumference, even though it is a semi-circle, because we have 2 halves they equal a whole.

Finally we have our parts and we add them up.

220+131.88=351.88

So from this we can determine it'd be the 2nd answer. 351.88.

Answer 33

@Devum u still here

Answer 34

\(\color{#0cbb34}{\text{Originally Posted by}}\) @javonarnold
@Devum u still here
\(\color{#0cbb34}{\text{End of Quote}}\)
Yeah I'm still here. What's up?

Answer 35

I was boutta head to sleep tho its gettin late ;-;

Answer 36

ok