Question

Solve for z.
Reduce any fractions to lowest terms. Don't round your answer, and don't use mixed fractions.
-4z+31≥ 17z + 23

Answer 1

Pleaseee helpp!

Answer 2

I dont even know..

Answer 3

bruh then please dont answer, im really struggling

Answer 4

oop

Answer 5

What do you think the first step to do is?

Answer 6

The first thing I would do is combine the like terms from each side of the equation. For example, if there is -3x+5>9x+2
You would combine -3x and 9x together, as well as combine 5 and 2
Then the equation would become 3>12x
After that, all you need to do is divide 12 on both sides to get x by itself

Answer 7

I politely disagree with the previous reply
We have \(−4z+31≥17z+23\)
And the first step would be to get `17z` and subtract it from both sides of the equation
which would give us \(−21z+31≥23\)
Basically what we just did was \(−4z+31−17z≥17z+23−17z\)
So now we have to subtract 31 from both sides of the euqation
which would give us \(−21z≥−8\)
because \(−21z+31−31≥23−31\longrightarrow −21z≥−8\)
Then we divide both sides by `-21`
\(\LARGE\frac{-21z}{-21}=\frac{-8}{-21}\)
So -21z/-21 cancels out
so all you have left is -8/-21
so once that is simplified you should get your answer
\(\frac{-8}{2-1}=?\)

If we did what MrMudd suggested we would be doing \(3>12x\)
\(\frac{3}{12}=\frac{12x}{12}\)

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie
I politely disagree with the previous reply
We have \(−4z+31≥17z+23\)
And the first step would be to get `17z` and subtract it from both sides of the equation
which would give us \(−21z+31≥23\)
Basically what we just did was \(−4z+31−17z≥17z+23−17z\)
So now we have to subtract 31 from both sides of the euqation
which would give us \(−21z≥−8\)
because \(−21z+31−31≥23−31\longrightarrow −21z≥−8\)
Then we divide both sides by `-21`
\(\LARGE\frac{-21z}{-21}=\frac{-8}{-21}\)
So -21z/-21 cancels out
so all you have left is -8/-21
so once that is simplified you should get your answer
\(\frac{-8}{-21}=?\)

If we did what MrMudd suggested we would be doing \(3>12x\)
\(\frac{3}{12}=\frac{12x}{12}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
Fixing a typo.

Answer 9

@MrMudd183??

Answer 10

yeah? sorry....i'm doing my own hw and not fully paying attention. what supie said is more in depth, i was doing a simple explination to try and not cause confusion

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183
yeah? sorry....i'm doing my own hw and not fully paying attention. what supie said is more in depth, i was doing a simple explination to try and not cause confusion
\(\color{#0cbb34}{\text{End of Quote}}\)
Yes thanks.

Next time if you cant put your full attention on helping someone just don't do it
because it seems to be that this time you gave a incorrect answer.

Answer 12

I tried to explain in a simple way but yet make it descriptive by doing an example problem

Answer 13

Oh ok.

Answer 14

ok ok so im confused whats th answer

Answer 15

nvmm