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Mathematics 20 Online
lilcutie2:

help math again sorry

snowflake0531:

tqhagye4rfdv ss

lilcutie2:

snowflake0531:

fdvcq5rgt just use the equations AZ give, plug in the lengths... and find the missing side..

lilcutie2:

I'm stupid

snowflake0531:

no, it's not stupidity, just take the equations over that have the value RQ in it

snowflake0531:

and he's here, ask him lol bye

itsmehjay:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 and he's here, ask him lol bye \(\color{#0cbb34}{\text{End of Quote}}\) congrats on purple ;oo

snowflake0531:

thxxxx

lilcutie2:

@az

snowflake0531:

he's observing rn lol, wait a moment

AZ:

so this was your image from your previous question|dw:1614867519440:dw|

lilcutie2:

ok

lilcutie2:

so do you subtract

AZ:

so for your second question in the previous post, remember we got \(\dfrac{BA}{QP} = \dfrac{CB}{RQ}\)

AZ:

you have to use the numbers from the sides

lilcutie2:

so divide

AZ:

|dw:1614867647594:dw|

lilcutie2:

now divde

AZ:

put those numbers into \(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ so for your second question in the previous post, remember we got \(\dfrac{BA}{QP} = \dfrac{CB}{RQ}\) \(\color{#0cbb34}{\text{End of Quote}}\)

lilcutie2:

yes

AZ:

and we can solve for RQ because we know BA = 20 CB = 15 QP = 12

lilcutie2:

so how do we solve for rq

AZ:

put those numbers in

AZ:

\( \dfrac{BA}{QP} = \dfrac{CB}{RQ}\) \(\dfrac{20}{12} = \dfrac{15}{RQ}\) so can you solve for RQ now?

lilcutie2:

so do 15*12=180

AZ:

and then divide by 20

lilcutie2:

so rq=9

AZ:

that's your answer!

lilcutie2:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ that's your answer! \(\color{#0cbb34}{\text{End of Quote}}\) thanks

AZ:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @lilcutie2 thanks \(\color{#0cbb34}{\text{End of Quote}}\) You're welcome!

lilcutie2:

@lucasp16

snowflake0531:

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