help math again sorry
tqhagye4rfdv ss
fdvcq5rgt just use the equations AZ give, plug in the lengths... and find the missing side..
I'm stupid
no, it's not stupidity, just take the equations over that have the value RQ in it
and he's here, ask him lol bye
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 and he's here, ask him lol bye \(\color{#0cbb34}{\text{End of Quote}}\) congrats on purple ;oo
thxxxx
@az
he's observing rn lol, wait a moment
so this was your image from your previous question|dw:1614867519440:dw|
ok
so do you subtract
so for your second question in the previous post, remember we got \(\dfrac{BA}{QP} = \dfrac{CB}{RQ}\)
you have to use the numbers from the sides
so divide
|dw:1614867647594:dw|
now divde
put those numbers into \(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ so for your second question in the previous post, remember we got \(\dfrac{BA}{QP} = \dfrac{CB}{RQ}\) \(\color{#0cbb34}{\text{End of Quote}}\)
yes
and we can solve for RQ because we know BA = 20 CB = 15 QP = 12
so how do we solve for rq
put those numbers in
\( \dfrac{BA}{QP} = \dfrac{CB}{RQ}\) \(\dfrac{20}{12} = \dfrac{15}{RQ}\) so can you solve for RQ now?
so do 15*12=180
and then divide by 20
so rq=9
that's your answer!
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ that's your answer! \(\color{#0cbb34}{\text{End of Quote}}\) thanks
\(\color{#0cbb34}{\text{Originally Posted by}}\) @lilcutie2 thanks \(\color{#0cbb34}{\text{End of Quote}}\) You're welcome!
@lucasp16
post another question
Join our real-time social learning platform and learn together with your friends!