Question

I NEED SOMEONE GOOD AT ALGEBRA TO DM ME PLSS HURRY DEADLINE IS VERY SOON!

Answer 1

post ur questions here

Answer 2

i cant put a pic here though
well if i can idk how

Answer 3

click attach file

Answer 4

right now you have your function in vertex form, we can rewrite this
4(x+1)^2 -3
What do you think is the first step?

Answer 5

I am walking it through with you step by step, so you know how to solve problems like this inthe future

Answer 6

O_O

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
I am walking it through with you step by step, so you know how to solve problems like this inthe future
\(\color{#0cbb34}{\text{End of Quote}}\)
to label the a b and c of the equation?

Answer 8

hmm ok, well what happens when you expand the square (x+1)^2
do u know how?

Answer 9

well we would need to find a, b and c first, thats our first step

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
hmm ok, well what happens when you expand the square (x+1)^2
do u know how?
\(\color{#0cbb34}{\text{End of Quote}}\)
nope that why i asked this question

Answer 11

alright, so order of operations, first parenthesis, then exponents, than multiplication/division
then addition/subtraction

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
alright, so order of operations, first parenthesis, then exponents, than multiplication/division
then addition/subtraction
\(\color{#0cbb34}{\text{End of Quote}}\)
PEMDAS!!!!!!!!!!!!!!!!!!

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
right now you have your function in vertex form, we can rewrite this
4(x+1)^2 -3
What do you think is the first step?
\(\color{#0cbb34}{\text{End of Quote}}\)
So you see here, the first step would be to expand the square, since we cant simplify anything within the parenthesis
and yes pemdas!
Since (x+1)^2 has an exponent, this is what we simplify first

Answer 14

\[(x+1)^2=(x+1)(x+1)\]
you can then distribute that above
or use the formula \[(a+b)^2 = a^2+2ab+b^2\]
where a is x and b is 1 in this case

Answer 15

noooooooooo thats why i askeddddddd. hmmm distrbute. nope idk how

Answer 16

bro i be livin in rona world idk anything anymore

Answer 17

well we would actually use FOIL, if you have heard of it, First, then inner, then outer then last
what this means is that we take the first 2 terms and multiply, then add the product of the inner terms, then add the product of the outer 2 terms and then add the product of the last 2 terms

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
well we would actually use FOIL, if you have heard of it, First, then inner, then outer then last
what this means is that we take the first 2 terms and multiply, then add the product of the inner terms, then add the product of the outer 2 terms and then add the product of the last 2 terms
\(\color{#0cbb34}{\text{End of Quote}}\)
oh yeah i rememebr the teacher talking about the foil thingy

Answer 19

this in action would look something like thi
this is an example problem of how foil works, so I had (x+2)(x+5)
I labeled the arrows by order, although it isnt the end of the world if u dont do it in the right order , its good to have your work organized, so take my advice its the easiest way
So we do first: x times x we get x^2
outer : x times 5 we get 5x (these are the outer 2 terms)
inner: 2 times x we get 2x (these are the inner 2 terms)
last: 5 times 2 we get 10 (these are the last 2 terms)

Answer 20

apologize for the legendary handwriting ahead of time :)

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
apologize for the legendary handwriting ahead of time :)
\(\color{#0cbb34}{\text{End of Quote}}\)
hehehe its ok

Answer 22

tell me when you understand what we did in that sample problem, (x+1)(x+1) involves close to the same steps, if you have more questions ask away!

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
tell me when you understand what we did in that sample problem, (x+1)(x+1) involves close to the same steps, if you have more questions ask away!
\(\color{#0cbb34}{\text{End of Quote}}\)
wait what? the answer is (x+1)(x+1)?

Answer 24

no thats the problem you are trying to solve, forget about that, focus on the sample problem (x+2)(x+5) \(\color{#0cbb34}{\text{Originally Posted by}}\) darkknight
this in action would look something like thiCreated with RaphaëlReply Using Drawing
this is an example problem of how foil works, so I had (x+2)(x+5)
I labeled the arrows by order, although it isnt the end of the world if u dont do it in the right order , its good to have your work organized, so take my advice its the easiest way
So we do first: x times x we get x^2
outer : x times 5 we get 5x (these are the outer 2 terms)
inner: 2 times x we get 2x (these are the inner 2 terms)
last: 5 times 2 we get 10 (these are the last 2 terms)
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 25

O_O

Answer 26

ugh im done

Answer 27

please dont give up, we got this, and when i say we i mean u and me.
read it slowly, if u need help with anything ask away,ask the parts you dont understand or need clarification

Answer 28

thx for the help.

Answer 29

we rnt done yet

Answer 30

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
we rnt done yet
\(\color{#0cbb34}{\text{End of Quote}}\)
yea ik i just cant my head is like anfaoidnf paoid faosdifno andsfoasdaosdf

Answer 31

how about you take a break, its not too hard of a problem, you got it. Take like a 15 min brake and cool off, refresh your mind

Answer 32

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
how about you take a break, its not too hard of a problem, you got it. Take like a 15 min brake and cool off, refresh your mind
\(\color{#0cbb34}{\text{End of Quote}}\)
see you in ten years!

Answer 33

... you are wasting your own effort and mine too :\ your choice in the end though,

Answer 34

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight
... you are wasting your own effort and mine too :\ your choice in the end though,
\(\color{#0cbb34}{\text{End of Quote}}\)
im just gonna go on a diffrent question those are to hard