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Mathematics 12 Online
100kpimpcess:

help @Aqual plzzzz ss below

100kpimpcess:

100kpimpcess:

@Astrid1

100kpimpcess:

@MrMudd183 or @QuestionCoveBot

QuestionCoveBot:

I'm sorry, I am not able to do this type of math. snowflake, darkknight can.

snowflake0531:

i'm busy

MrMudd183:

So triangle XYZ is scaled down from JKL, do you know by how much?

100kpimpcess:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 So triangle XYZ is scaled down from JKL, do you know by how much? \(\color{#0cbb34}{\text{End of Quote}}\) 7?

MrMudd183:

Not quite, the vertial axis of JKL is 4 units up, while XYZ is 2, and then line KL is 8 units across. Knowing that lines JL and XZ are a differents of two/half, what do you think the unit difference for lines JL and XZ will be?

100kpimpcess:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 Not quite, the vertial axis of JKL is 4 units up, while XYZ is 2, and then line KL is 8 units across. Knowing that lines JL and XZ are a differents of two/half, what do you think the unit difference for lines JL and XZ will be? \(\color{#0cbb34}{\text{End of Quote}}\) idk im a little confused

MrMudd183:

It's alright, let's work it out together. We know that lines JL and XZ have a difference of 2/half, so we know one measurement of XYZ

100kpimpcess:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 It's alright, let's work it out together. We know that lines JL and XZ have a difference of 2/half, so we know one measurement of XYZ \(\color{#0cbb34}{\text{End of Quote}}\) ok

MrMudd183:

I'm thinking the triangle JKL was scaled down by a half factor *1/2* to create triangle XYZ, if that's the case then line ZY would be half of KL *I'm sorry, I was using the wrong label names the whole time...my fault*

100kpimpcess:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 I'm thinking the triangle JKL was scaled down by a half factor *1/2* to create triangle XYZ, if that's the case then line ZY would be half of KL *I'm sorry, I was using the wrong label names the whole time...my fault* \(\color{#0cbb34}{\text{End of Quote}}\) its ok so 4?

MrMudd183:

Correct, count over four units to the left or right? Remember the triangle was scaled down by half AND was reflected over the Y-Axis

100kpimpcess:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 Correct, count over four units to the left or right? Remember the triangle was scaled down by half AND was reflected over the Y-Axis \(\color{#0cbb34}{\text{End of Quote}}\) i got 2 on the y-axis

MrMudd183:

That's correct, so we can eliminate both A and D Which leaves us with B and C

MrMudd183:

wait, leave A

100kpimpcess:

ok

MrMudd183:

So it's (??,2), what do you think the X-axis measurement is?

100kpimpcess:

-6?

MrMudd183:

Correct, good job!

100kpimpcess:

so its (-6,2) and (6,2)?

MrMudd183:

The question is saying "select all that apply" so if the triangle wasn't reflected and only translated w/scaling... Yep, try those two

100kpimpcess:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 The question is saying "select all that apply" so if the triangle wasn't reflected and only translated w/scaling... Yep, try those two \(\color{#0cbb34}{\text{End of Quote}}\) its says atleast one of them i incorrect

100kpimpcess:

is*

MrMudd183:

Hmmm, I'd try removing the (6,2) and just stick with (-6,2)

100kpimpcess:

its was A and B

100kpimpcess:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 Hmmm, I'd try removing the (6,2) and just stick with (-6,2) \(\color{#0cbb34}{\text{End of Quote}}\) i can get a similar question and try again

MrMudd183:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @100kpimpcess \(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 Hmmm, I'd try removing the (6,2) and just stick with (-6,2) \(\color{#0cbb34}{\text{End of Quote}}\) i can get a similar question and try again \(\color{#0cbb34}{\text{End of Quote}}\) Okay, do you understand how they are worked out now? *Is it a bit easier to understand*

100kpimpcess:

yes

100kpimpcess:

Thank you

MrMudd183:

You're welcome, if you ever need help feel free to @ me

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