Question

math problem

Answer 1

Split the graph into two right down the vertex

that way it'll be a one-to-one function

Answer 2

i split it but i cant find other points

Answer 3

that's all

what is the x-values of the left half

and the x-values of the right half

Answer 4

2 and 4?

Answer 5

One of those is wrong

We want the two intervals to be either

Answer 6

the points have to be on either side

it can't cross over otherwise it wouldn't be one-to-one anymore

Answer 7

2 and 4 are crosing?!

Answer 8

sorry im not sure

Answer 9

what is 2

answer choice 2 says [3, 7]

when x is from 3 all the way to 7

is it on one side of the line?

yes, right?

so that means it's a valid interval for it to be a one-to-one function

Answer 10

1,6?

Answer 11

-1,3?

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop
1,6?
\(\color{#0cbb34}{\text{End of Quote}}\)

no, when it goes all the way to 6, don't you see it won't be one-to-one anymore?

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop
-1,3?
\(\color{#0cbb34}{\text{End of Quote}}\)

yes

Answer 14

its -1,3 and 3,7?

Answer 15

az

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop
its -1,3 and 3,7?
\(\color{#0cbb34}{\text{End of Quote}}\)

Yup!

Answer 17

i split it?

Answer 18

-8,-4 doesnt pass through any lines?

Answer 19

Yes, split it just like last time

\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop
-8,-4 doesnt pass through any lines?
\(\color{#0cbb34}{\text{End of Quote}}\)

that's right

and what else?

Answer 20

im not sure

Answer 21

-8, -1?

Answer 22

look at -8, -1

it's the entire thing

is that one-to-one?

Answer 23

-5,-3?

Answer 24

look at it from -5 to -3

Look at the line between the red lines

Is that a one-to-one function?

Answer 25

its not

Answer 26

-4,0?

Answer 27

az

Answer 28

\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop
-4,0?
\(\color{#0cbb34}{\text{End of Quote}}\)

You got it!!

Answer 29

thanks

Answer 30

you're welcome