math problem
First solve for f(-1) in -x-4, when x is -1, what is it
-5
Yep, so we then do g(-5) -x^2 -3x -1, when x is -5
-41
Actually, it would be -25 + 15-1
hats next
What is -25+15-1
-11
So there's your answer
@AZ
\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop -5 \(\color{#0cbb34}{\text{End of Quote}}\) -(-1) - 4 = 1 - 4 = -3
plug in x = -3 into g(x)
the mistake you made initially was that when you plugged in x = -1 into f(x) you didn't realize there was already a negative sign in front of the x so it was -x and x is -1 so -x is going to be -(-1) which is +1
-9-9-1
be careful you got the first -9 correct but after that we have -3x and plugging in -3 gets us -3 (-3) = ?
9
yes so we go from -x^2 - 3x -1 \( = -(\color{red}{-3})^2 - 3(\color{red}{-3}) - 1\) \( = -9- (-9) - 1\) \( = -9 + 9 - 1\) does that make sense?
yep
-1
you got it!
\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop -5 \(\color{#0cbb34}{\text{End of Quote}}\) not is -5 f(-1) ATTENTION PLEASE !!!! f(x)= -x -4 f(-1) = -(-1) -4 = +1 -4 = -3 f(-1) = -3
ohh ok now i see that @AZ corrected it above ...
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