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Solve using substitution.. y=2x+7 3x -y = -9
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\[y=2x+7\] \[3x-y=-9\] Can you plug the first equation into the second?
Oh yeah uhhh 3x - (2x + 7) = -9??
Yep!!!!! so now distribute out the parenthesis, and then solve for x
2x + 7 = 9x?
3x - 9x = -6x..
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Where are you getting this lol \[3x-(2x+7)=-9\] Imagine the negative sign as negative 1 And do the distributive property So, the signs will change and become \[3x-2x-7=-9\] now can you solve for x?
oh ok so x - 7 = -9 x = -9 + 7 x = -2? o:
Yep So now plug in the x into one of the equations to get y
I'll use the first one y=2 (-2) + 7
y= -4 + 7 y= 3
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Yep~
Wowie your smort thank you so much >.<
why, thank you xd and yw~
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