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3x + 1 over 4y2 What is the value of the expression above when x = 3 and y = 4? You must show all work and calculations to receive full credit.
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\[\frac{ 3x+1 }{ 4y^2 }\] where \[x=3 \]\[y=4\]
So we have \[\frac{ 3(3)+1 }{ 4(4^2) }\] can you simplify that
slow down -- first of all is it \[ \frac{3x + 1} {4y^2} \] or \[ 3x + \frac {1} {4y^2} \]
you there mate? @yeetantor
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Florisalreadytaken slow down -- first of all is it \[ \frac{3x + 1} {4y^2} \] or \[ 3x + \frac {1} {4y^2} \] \(\color{#0cbb34}{\text{End of Quote}}\) those two don't equal....
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exactly
because it its the second one, we just failed to answer the thing properly lol
It's obviously the first one-
if*
it didnt say "ALL OVER"
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