helefppelppe
What
You need to know the exponent rules \(\Large a^b \times a^c = a^{b+c}\)
So for #1 then what is \(\large a^5 \times a^3 = ??\) Just add the exponents
8 ?
Yes so what's your final answer?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @sxdsouls 8 ? \(\color{#0cbb34}{\text{End of Quote}}\) yeah
a^8 ?
Exactly
oktytyytytytytyt
For the second one Multiply the numbers and then multiply \(\large a^7 \times a^8\) what do you get?
a^56 ?
no no no when you're multiply, you ADD the exponents \( 2a^7 \times 3 a^8 = 2 \times 3 \times a^7 \times a^8\)
oh add i saw multiply
you multiply 2 and 3 but when you're multiplying a^7 and a^8, you're going to add the exponents
2 x 3 = 6 7+ 8 = 15
so put it all together now
15 + 6 = 21
no
wait oops
a^15 ? djwkekql
\( 2a^7 \times 3 a^8 = 2 \times 3 \times a^7 \times a^8\) what is 2 times 3 and then a^7 * a^ 8
a^7 * a^8 is a^15 yes so we get \( 2 \times 3 \times a^{15}\) what is 2 times 3
6 ^^
so we get \( 6 \times a^{15}\) and another way to write that is \( 6 a^{15}\)
Does that make sense?
sorta but sounds ez-
\( 6a^{15}\) is just 6 multiplied with \(a^{15}\)
Okay, last one now You need to learn a new exponent rule: \(\Large (ab)^c = a^c b^c\) basically when you have an exponents on the outside of the parenthesis, you can distribute it inside to each term so what is \( (2x)^3 = ?/\)
actually i totally got it tyyy B) <3
what do you get for the last one :))
idkkk bcc my time wasss uppp so it doesnt matter nowowowow
you can still solve it \(\Large (ab)^c = a^c \times b^c\) so what is \(\Large (2x)^3 = ??\)
Do you want colors?? \(\Large (\color{red}{a}\color{orange}{b})^\color{cyan}{c} = \color{red}{a}^\color{cyan}{c} \times \color{orange}{b}^\color{cyan}{c}\) so what is \(\Large (\color{red}{2}\color{orange}{x})^\color{cyan}{3} = ??\)
igiveup;)
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