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Mathematics 8 Online
100kpimpcess:

help ss below

100kpimpcess:

100kpimpcess:

@snowflake0531

100kpimpcess:

its like the last one

100kpimpcess:

40 is the hypo and 25 and x are the legs?

snowflake0531:

These are two different triangles, in one, 2 sides are 40, you want to find the hypotenuse In the second one, you have 25 and 35 and the two sides, and want to find the hypotenuse

snowflake0531:

So, as we said earlier \[a^2+b^2=c^2\] looking at the first triangle, with a and b both equal to 40 how would you write the equation?

100kpimpcess:

80?

100kpimpcess:

im so confused imma ask my teacher tmrw

100kpimpcess:

yeah

snowflake0531:

well, that turned out wrong, but ok

100kpimpcess:

thank you tho

snowflake0531:

uh so we have \[40^2+40^2=c^2\] simplify that

snowflake0531:

What's 40^2, plus itself

100kpimpcess:

3,200

snowflake0531:

Yes so 3200 = c^2 what does c equal

100kpimpcess:

3200?

snowflake0531:

\[c^2=3200\] \[\sqrt c^2 = \sqrt3200\] \[c=\sqrt3200\]

100kpimpcess:

simpfly?

snowflake0531:

we can use the calculator for the sqrt3200 later now for the next triangle 25 and 35 are the sides so we have \[25^2+35^2=c^2\]

snowflake0531:

So, add 25^2 and 35^2 first

100kpimpcess:

1850

snowflake0531:

so c = sqrt1850

100kpimpcess:

43.0

snowflake0531:

So, obviously with sqrt3200 and sqrt1800, sqrt1800 is smaller, which means James ran less And to find the difference between them, convert the two into decimals

snowflake0531:

*1850 oops

100kpimpcess:

ok thank yu

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