Intersection of Chords
Find x
It's not 4
@AZ
|dw:1618023416917:dw|
so 8 *4 = 2 * x solve for 'x'
@Allison is given somewhere that this chords are equal length ? or how come this to @AZ ?
|dw:1618037678652:dw| so my opinion that to find x more easy to use the proportionality of corresponding sides and in this way you can write
\[\frac{ x }{ 4 }= \frac{ 8 }{ 2 } => x = ?\]
16
yes in this way x = 16
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 @Allison is given somewhere that this chords are equal length ? or how come this to @AZ ? \(\color{#0cbb34}{\text{End of Quote}}\) It is the intersecting chord theorem "When two chords intersect each other inside a circle, the products of their segments are equal." https://www.mathopenref.com/chordsintersecting.html#:~:text=Each%20chord%20is%20cut%20into,matter%20where%20the%20chords%20are. Your method led to the same answer :)
Join our real-time social learning platform and learn together with your friends!