Question

Assume that fur color in mice is controlled by a single allele combination and shows a complete dominance pattern of inheritance. The dominant allele (B) codes for black fur and the recessive allele (b) codes for brown fur. Two heterozygous mice (Bb) are crossed. What percent of their offspring will have black fur?

Answer 1

Set up your punnette Square

Answer 2

alright

Answer 3

@boredfr

Answer 4

60%?

Answer 5

How did you set up your punnette square?

Answer 6

using four suares

Answer 7

Do you have a picture of your punnet square?

Answer 8

im not sure ho to solve using the punnette suare

Answer 9

How to solve a punnet square link:
https://www.youtube.com/watch?v=agQpPPQ5IVQ

I hope that helps!
ℂ𝕣𝕖𝕖𝕕

Answer 10

but ho do i find the percent

Answer 11

Ok so each square is 25%

Answer 12

So how many squares have (B)?

Answer 13

3

Answer 14

Ok now multiply 25 by 3

Answer 15

75

Answer 16

The answer is 75%

Answer 17

So, based on the punnet square,



BB, Bb- Will have black fur

bb- Will have brown fur

Now by using each of those squares,

You will find that,

75% of them will be black; as it is a 3:4 Ratio
&
25% of them will be brown; as it is a 1:4 Ratio.

Answer 18

thanks

Answer 19

Exactly, what boredfr said.

Your welcome!
ℂ𝕣𝕖𝕖𝕕

Answer 20

Good Teamwork boredfr!
I appreciate the assistance! :)