Yes, So if the frames area is 48 inches what would you do with the extra 1 inch
marissabartoldo:
multiply?
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Astro:
Ok, The picture has a 1 inch frame what would that mean?
marissabartoldo:
the frame is one inch wide
Astro:
Yes, But what does that mean for the problem. What would you do?
Astro:
@boredfr
marissabartoldo:
I don't know
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boredfr:
|dw:1619107739136:dw|
boredfr:
You need to figure out the dimensions of the frame in order to find the dimensions of the picture to calculate the area
boredfr:
So if the frame and picture is spare (even though I drew a rectangle) then what times its self will give you 48?
marissabartoldo:
6.928
Florisalreadytaken:
What? that doesnt make sense
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Florisalreadytaken:
|dw:1619108737384:dw|
marissabartoldo:
@boredfr wrote:
;-; um well yh ok so basically one inch less then what would me 5.928 so then multiply that by its self
it was wrong
Florisalreadytaken:
because it is wrong...
marissabartoldo:
wait so how do you do it
Florisalreadytaken:
what we are asked to find, is just that middle square part -- to find that we run into 2 very simple equations
x+2 would be one of the sides -- since we will find the area of the \( \square \), we have got 2 of that -- so the area of the whole thing would be
\( Area = (x+2)(x+2) \)
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Florisalreadytaken:
and the area of the painting itself would be x
\( Area_{\;\square} = x \times x \)
Florisalreadytaken:
lets put it all together in 1 equation -- so the are of the whole thing, minus the area of just the painting
\[ Area\;\square = (x+2)(x+2) -( x \times x)\]
Florisalreadytaken:
do the math and reply when you have an answer lol.
Florisalreadytaken:
oh i forgot -- we know that the area of the whole thing is 48 inches \( ^2 \) right?
so the proper equation would be
\(48 = (x+2)(x+2) -( x \times x)
\)
marissabartoldo:
4x^2?
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Florisalreadytaken:
what? how did you get that?
Florisalreadytaken:
@marissabartoldo wrote:
4x^2?
you are pretty close tho -- you might have made a mistake while factoring -- anyway it actually would be \( 4x \).
so \( 4x=[48 -(2 \times 2)] \Rightarrow x=11 \)
Florisalreadytaken:
@florisalreadytaken wrote:
and the area of the painting itself would be x
[color= inherit;][/color]\( Area_{\;\square} = x \times x \)