Hemophilia, a blood clotting disorder, is a sex-linked recessive trait. In order to express hemophilia, females need two copies of the allele. Men, however, only need one copy of the gene to express hemophilia. A woman who is a carrier for hemophilia (heterozygous) has a child with a man who does not have hemophilia. Complete the Punnett square below. Answers may be used more than once.

Question

Hemophilia, a blood clotting disorder, is a sex-linked recessive trait.  In order to express hemophilia, females need two copies of the allele.  Men, however, only need one copy of the gene to express hemophilia.  A woman who is a carrier for hemophilia (heterozygous) has a child with a man who does not have hemophilia.  Complete the Punnett square below.  Answers may be used more than once.

klmjnmkj · Answer

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AZ · Answer

Can you fill out the Punnett square?

HaydenwH · Answer

your not supposed to do it for them..

KingPizza · Answer

for punnet squares that already have the top and side filled in for you, you should take what's from the direct left and top from each square and put it in the appropriate square. Please let me know if this explanation is confusing.

AZ · Answer

$\sf X^{H}Y$ is the unaffected father

$\sf X^{H} X^{h}$ is the carrier mother

so if they have $\sf X^{h}$ along with a Y chromosome, then that means they'll be affected

but if they have an $\sf X^{h}$ with a normal X chromosome ($\sf X^{H}$) then they'll be a carrier
If they have two $\sf X^h X^h$ then they'll be an affected female

AZ · Answer

keep in mind

lower case h = carrier or affected
you need only one to be affected if you're a male
you need two to be affected if you're a female
and if you're a female and only have one, then you're a carrier

upper case H = normal, not carrying that trait

klmjnmkj · Answer

thanks

AZ · Answer

remember

males are XY

females are XX

AZ · Answer

You're welcome!

If you want me to check your answer, let me know

KingPizza · Answer

@az wrote:

$\sf X^{H}Y$ is the unaffected father $\sf X^{H} X^{h}$ is the carrier mother so if they have $\sf X^{h}$ along with a Y chromosome, then that means they'll be affected but if they have an $\sf X^{h}$ with a normal X chromosome ($\sf X^{H}$) then they'll be a carrier If they have two $\sf X^h X^h$ then they'll be an affected female

yes I agree with that explanation so keep that in mind when you answer questions related to this

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