Question

A number is chosen at random from the first 100 positive integers. Find the probability that the number is either even or a perfect square.

11/20
1/20
3/5

Answer 1

From 1 to 100 there are 50 even numbers
And about perfect squares, we have from 1 to 10
\[1^2=1~2^2=4~3^2=9~4^2=16~5^2=25~6^2=36~7^2=49~8^2=64~9^2=81~10^2=100\]
so we have
1, 4, 9, 16, 25, 36, 49, 64, 81, 100

And out of these, 4, 16, 36, 64, 100 are even numbers
So besides for those 5, there are 5 more that are odd, so there are 55 numbers that are either even or a perfect square

So that's 55/100

Answer 2

So then from there you can simplify 55/100

Answer 3

so how you divided ?

Answer 4

?
I didn't divide anything

Answer 5

the other guy