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When x=3 and y=-6, what is n? x^2-16+7*y=n
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So.... \[3^2-16+7*-6=n\]
Do... \[3^2\]...to get 9. Then you have: \[9-16+7*-6=n\]
What's 9-16+7 then?
0?
Yes. And when you multiply/divide by 0, the end answer is always 0. (: so then, obviously, 0*-6 is 0. Which then makes n=0 so therefore, n=0
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Thanks :)
yur welcome- xD
also congrats on purple (:
@questioncovebot wrote:
So....
\[3^2-16+7*-6=n\]
Don't listen to QuestionCoveBot he's actually a bot at math.
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n = 3^2 -16 + 7 * -6
I already did this, and the question is answered. No need to answer it again. >.>
7 * -6 = -42 so n = 3^2 - 16 -42
You're wrong. Lol.
3^2 -58
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9 - 58
n = -49
@questioncovebot explain to me how it's n = 0 and not n = -49
;)
@questioncovebot wrote:
Do...
\[3^2\]...to get 9.
Then you have:
\[9-16+7*-6=n\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Actually a clown.
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